 | James Morgan Rawlins - Arithmetic - 1899 - 458 pages
...= ty = 4J mo. Hence the rule, briefly stated, is : 1. Multiply the debts by the terms of credit. 2. Divide the sum of the products by the sum of the debts. PROBLEMS. 1. Equate the time for payment of $400, due in 3 mo. ; $600, due in 7 mo. ; and $300, due... | |
 | Edward Gideon - 1902 - 272 pages
...term of credit of each debt. III. Multiply each debt by its term of credit from the standard date, and divide the sum of the products by the sum of the debts for the average term of credit. IV. Add the average term of credit to the standard date for the average... | |
 | David Eugene Smith - Arithmetic - 1905 - 144 pages
...following is true: To find the average term of credit, multiply each debt by its term of credit and divide the sum of the products by the sum of the debts. The following examples may be used if desired: 1. A owes B $30 due in 4 mo., $40 due in 5 mo., and $80... | |
 | Civil engineering - 1906 - 590 pages
...first debt is due, find the term of credit for each debt. Multiply each debt by its term of credit, and divide the sum of the products by the sum of the debts. The quotient to the nearest integer will be the number of days from the date of reference to the equated time. EXAMPLES... | |
 | 1922 - 906 pages
...by either the debtor or creditor. The common rule is: Multiply each debt by its term of credit, and divide the sum of the products by the sum of the debts. The quotient will be the average term of credit. This added to the date from which the credits were reckoned will give the average... | |
 | Peder Lobben - Mechanical engineering - 1922 - 512 pages
...different lengths of time, the average time is calculated by this rule: Multiply the debt by the time ; divide the sum of the products by the sum of the debts, and the quotient is the time when all the debts may be considered due. EXAMPLE. A owed B $600, due... | |
 | Encyclopedias and dictionaries - 1922 - 886 pages
...by either the debtor or creditor. The common rule is: Multiply each debt by its term of credit, and divide the sum of the products by the sum of the debts. The quotient will be the average term of credit. This added to the date from which the credits were reckoned will give the average... | |
 | George Ernest Clark - 1884 - 128 pages
...1 approximately. Ans. (14) Multiply each debt into the time that will elapse before it becomes due; then divide the sum of the products by the sum of the debts. The quotient will be the equated time required. £ months. £ 375 x 4 = 1500 28H x 5 = 1406Í 6 = 562k - 750 = 4| months. Ans. For proof... | |
 | Daniel Barnard Hagar - Arithmetic - 1871 - 352 pages
...average time of their payments ? 581. Rules.— Multiply each of the debts by its term of credit, and divide the sum of the products by the sum of the debts ; the quotient will be the average term of credit. Or, Find the interest of each debt for its term of credit, and divide the sum... | |
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Multiply each debt by its term of credit and divide the sum of the products by the sum of the debts. The quotient will be the average term of credit. 
