 | Johann Georg Heck - Encyclopedias and dictionaries - 1860 - 332 pages
...any part of the vernier, consequently, for 10 divisions of the limb, we must add 10 minutes ; then, 36° 30' + 10 = 36° 40'. If the divisions thus met,...by the foot level. This is an isosceles triangle, ahc, from whose vertex depends a plumb line, cf. If this be placed upon a board, and one end elevated... | |
 | Adrien Marie Legendre - Geometry - 1871 - 490 pages
...to DAC, and BDA to CDA : hence, the last two are right angles. Consequently, a stra1ght line drawn from the vertex of an isosceles triangle to the middle of the lase, lisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM.... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...to DAC, and BDA to CD A : hence, the last two are right angles. Consequently, a stra1ght line drawn from the vertex of an isosceles triangle to the middle of the base, bisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM. If two... | |
 | William Guy Peck - Conic sections - 1876 - 376 pages
...their parts, (P. 11). Hence, the angle A is equal to C, which was to be proved. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the base bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been proved,... | |
 | William Guy Peck - Conic sections - 1876 - 412 pages
...parts, ( P. 11 ). Hence, the angle A is equal to C, which was to be proved. BOOX 1. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the bose bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been... | |
 | George Anthony Hill - Geometry - 1880 - 348 pages
...conclusionsare: CDbisects AB,a.nd CD bisects AC B. Prove by showing that AA CD I!. The line joining the vertex of an isosceles triangle to the middle of the base is perpendicular to the base, and bisects the angle at the vertex. Hints. — In -this case what are... | |
 | Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...equal to DAC, and BDA to CDA : hence, the last two are right angles. Consequently, a straight Hne drawn from the vertex of an isosceles triangle to the middle of the base, bisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM. // two... | |
 | Arthur Latham Baker - Geometry, Solid - 1893 - 150 pages
...equiangular, and the Sph. ^s at the base are equal, QED 273. COR. 9. The arc of a great circle drawn from the vertex of an isosceles triangle to the middle of the base, bisects the vertical angle, is perpendicular to the base, and divides the triangle into two symmetrical... | |
 | George Clinton Shutts - Geometry - 1894 - 412 pages
...of the base is perpendicular to the base, the triangle is isosceles. Ex. 29. Prove that a Une drawn from the vertex of an isosceles triangle to the middle of the base, (/) bisects the triangle, (2) bisects the vertical angle, (j) is perpendicular to the base. PROPOSITION... | |
 | Wilbur Fisk Nichols - 1905 - 208 pages
...the base. Prove that BD J- AC, and bisects AC. 3. Using the same figure, prove that the line joining the vertex of an isosceles triangle to the middle of the base is perpendicular to the base, and bisects the angle at the vertex. Prove BD -L AC, and that BD bisects... | |
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Hence a straight line drawn from the vertex of an isosceles triangle, to the middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts. 
