 | William Ruger - Arithmetic - 1836 - 274 pages
...and 20ft. long? Ans, 80yds. NOTE. — To obtain the surface of a plane, as a floor, field., if-e.- Multiply the length by the breadth, and the product will be the surface; then as the number of square feet in a yard of the carpeting which is 4,5 feet, is to one... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...Therefore, 26 X 26 =676 Sq. rods, and 676-M60=4a, 36r. the Answer. ART. 2. To measure a parallellograra, or long square. RULE. Multiply the length by the breadth,...product will be the area, or superficial content. EXAMPLES. 1. A certain garden, in form of a long square, is 96 11. long, and 54 wide ; how many square... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 290 pages
...which is the answer. TIMBER MEASURE. PROBLEM I. To find the superficial content of a board or plank. RULE. Multiply the length by the breadth, and the product will, be the area. BY THE CARPENTER'S RULE. Set 1 2 on B, to the breadth in inches on A ; then against the length in feet,... | |
 | Luther Ainsworth - Arithmetic - 1837 - 306 pages
...denomination required. Q. How do you find the superficial area of a parallelogram, or long square ? A. Multiply the length by the breadth, and the product will be the superficial area as before. 1. There is a garden, laid out in an exact square, measuring, on each side,... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...it stand upon ? PROBLEM IV. Answer, 4134.49 feet. TO FIND THE AREA OF A RECTANGLE. Rule.—Multiply the length by the breadth, and the product will be the area. Note. Buildings, streets, drains, new roads, &c., are in general rectangles; and artificers generally... | |
 | Nathan Daboll - 1839 - 220 pages
...whole number of square rods to acres.] Ans. 26 acres 1 r. 25 rods. PROB. ii. — To find the area of a parallelogram, or long square. RULE. Multiply the...by the breadth, and the product will be the area. EXAMPLES. 1. How many square yards of ground are contained in a garden which is 126 feet long and 65... | |
 | Jason M. Mahan - Arithmetic - 1839 - 312 pages
...given, to find the area ; or the area and one side given, to find the length of the other aide. RULE. 1. Multiply the length by the breadth, and the product will be the area. 2. Divide the area by one of the sides, and the quotient will be the adjacent side. Examples. 1. What... | |
 | Robert Goodacre - 1839 - 320 pages
...Example 1 29 Miscellaneous Questions. CASE 1. — To find the area of any rectangular superficies. Multiply the length by the breadth, and the product will be the area in square measure. In measuring superficies, in which the dimensions vary, it is common to take the... | |
 | Joseph Stockton - Arithmetic - 1839 - 216 pages
...32J perches. 3<2. To find the content of an oblong square piece of ground, called a parallelogram. RULE. Multiply the length by the breadth, and the product will be the answer. EXAMPLE. i 1. There is an oblong square piece of ground, A, B, C, D, the longest sides of which... | |
 | Charles Davies - Geometrical drawing - 1840 - 262 pages
...the more accurate methods by means of figures. PROBLEM I. 2. To find the area of a board or plank. RULE. Multiply the length by the breadth, and the product will be the content required.' Q.OEsT. — 1. What methods of measuring timber have already been explained ? 2.... | |
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To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content. 
