| Euclid - 1835 - 540 pages
...by BD, and because the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both; therefore... | |
| John Playfair - Geometry - 1836 - 148 pages
...right angles : therefore all the exterior angles are equal to four right angles. PROP. VI. THEOR. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, the triangles shall be equivalent. Let ABC, DEF be two... | |
| Mathematics - 1836 - 488 pages
...has the greater base, shall be greater than the angle contained by the sides of the other. XXVI. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles,... | |
| Charles Reiner - Geometry - 1837 - 254 pages
...angle acb; and the triangle bdc must coincide with the triangle abc, and be equal to it. M.—Hence, if two triangles have two angles of the one equal to two angles of the other, each to each, and have likewise one side equal to one side, how must these sides be situated in order... | |
| Andrew Bell - Euclid's Elements - 1837 - 290 pages
...equal to it ; therefore the angle BAC is greater than the angle EDF. PROPOSITION XXVI. THEOREM. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side ; namely, either the sides adjacent to the equal angles,... | |
| William Whewell - 1837 - 226 pages
...angle; therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
| Euclid, James Thomson - Geometry - 1837 - 410 pages
...is equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| A. Bell - Conic sections - 1837 - 180 pages
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
| Euclides - 1838 - 264 pages
...greater than the angle EDF. Wherefore, if two triangles, &c. Q. t, n. PROP. XXVI. THEOR. °V'.' If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, vis. either the sides adjacent to the equal angles,... | |
| Thomas Kerigan - Nautical astronomy - 1838 - 804 pages
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, two angles of the one equal to two angles of the other, viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
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