 | William James Milne - Arithmetic - 1877 - 402 pages
...complete divisor, the figure last found, multiply this divisor by the last figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...first left-hand period of the given number. Subtract this product from this first left-hand period, and to the remainder annex the next period for a new dividend. Add the figure of the root just found to the amount in the first column, multiply the sum by the same... | |
 | Samuel Mecutchen, George Mornton Sayre - Arithmetic - 1877 - 200 pages
...of the figure last found; the sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. If there are any more periods to be brought down, annex the next period to the last remainder, and... | |
 | Albert Newton Raub - Arithmetic - 1877 - 348 pages
...results to the trial divisor, and the divisor becomes complete. 5. Multiply the complete divisor by the second figure of the root, and subtract the product from the dividend. 6. If there be a remainder and any more periods, to this remainder annex the next period, and proceed... | |
 | William Guy Peck - Arithmetic - 1877 - 430 pages
...trial divisor. IV. Multiply the divisor thus completed by the trial figure of the root just found, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till all of the... | |
 | Stoddard A. Felter, Samuel Ashbel Farrand - Arithmetic - 1877 - 496 pages
...at unit's place. II. — Find the root of the left-hand period ; subtract its cube from the period, and to the remainder annex the next period for a new dividend. III. — Multiply the square of the root found by 300, for a trial divisor ; divide, and take the quotient... | |
 | Edward Olney - Algebra - 1878 - 516 pages
...WRITE IT AS THE HIGHEST ORDER IN THE ROOT. SUBTRACT THE SQUARE OF THIS FIGURE FROM THE PERIOD USED, AND TO THE REMAINDER ANNEX THE NEXT PERIOD FOR A NEW DIVIDEND. 3rd. DOUBLE THE HOOT ALREADY FOUND FOR A TRIAL DIVISOR, BY WHICH DIVIDE THE NEW DIVIDEND, REJECTING... | |
 | William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...divisor, and the sum will be the true divisor. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE.... | |
 | Edward Olney - Arithmetic - 1879 - 404 pages
...the tria' divisor, thus forming the True Dijisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period. IV. Repeat the process described in the last paragraph till the work is complete. When any trial divisor... | |
 | Robert Potts - Algebra - 1879 - 672 pages
...of the root. 5. Annex this figure to the trial divisor, and multiply the divisor so increased by the second figure of the root, and subtract the product from the dividend. 6. To this remainder annex the next period to form a new dividend, and find a new trial divisor by... | |
| |
Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
