 Divide the first term of the dividend by the first term of the divisor, the result will be the first term of the quotient.  College Algebra - Page 60by James Harrington Boyd - 1901 - 777 pagesFull view - About this book
 | Charles Davies - Algebra - 1859 - 324 pages
...dividend and divisor with reference to a (Art. 44), placing the divisor on the left of the dividend. Divide the first term of the dividend by the first term of the divisor ; the result will be the first term of the quotient, which, for convenience, we place under the divisor.... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 348 pages
...hand of the dividend, as in simple numbers. II. Find the first term of the quotient either by dividing the first term of the dividend by the first term of the divisor, or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...hand of the dividend, as in simple, numbers II. Find the first term of the quotient either by dividing the first term of the dividend by the first term of the divisor, or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply... | |
 | Robert Fowler - 1861 - 426 pages
...both the divisor and dividend according to the powers of the same letter (a in the example) ; then to divide the first term of the dividend by the first term of the divisor, place the result in the quotient and multiply the divisor by it ; subtract and proceed similarly with... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing the first term of the dividend by the first term of the divisor, thus arranged. The operation may then be continued in the manner of long division in Arithmetic ; each... | |
 | Benjamin Greenleaf - 1863 - 338 pages
...terms, 3а? с -\-6abc -f- 3 V с -{- 3 a c1.-f- 3 6 c1 -f- c", for a remainder or dividend. Dividing the first term of the dividend by the first term of the trial divisor, 3а1, we obtain c, the third term of the root. Adding together three times the square... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...divisor. (74.) From this investigation we deduce the following BULK FOR THE DIVISION OF POLYNOMIALS. 2. Divide the first term of the dividend by the first term of the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing the first term of the dividend by the first term of the divisor, thus arranged. The operation may then be continued in the manner of long division in Arithmetic; each... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...divisor with reference to the leading letter, and place the divisor on the right of the dividend. 2. Divide the first term of the dividend by the first term of the divisor, for the first term of the quotient. Multiply the divisor by this term, and subtract the product from... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...ONE POLYNOMIAL BY ANOTHER. 1. Arrange the dividend and Divisor with reference to a certain letter. 2. Divide the first term of the dividend by the first term of the divisor, for the first term of the quotient. Multiply the divisor by this term, and subtract the product from... | |
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