 | George Roberts Perkins - Arithmetic - 1850 - 356 pages
...side opposite the right angle is called the hypothenuse. It is an established proposition of geometry, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. From tfie above proposition, it follows that the square of the hypothenuse,... | |
 | George Roberts Perkins - Geometry - 1850 - 332 pages
...shall have (9+3)x(9-3)=12x6=9 " -3'=81-9=72. PROPOSITION VIII. THEOREM. In any right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the other two sides. Let ABC be a right-angled triangle, having the rightangle C ; then... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302. [Fig. 8.] 16. Hence, to find the different sides,... | |
 | Horace Mann - 1851 - 384 pages
...measured lines 10ft. apart. This mode of operation is founded on the property of right-angled triangles, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. A roof is said to have a true pitch, when the length of each rafter... | |
 | Charles William Hackley - Trigonometry - 1851 - 536 pages
...last, and a very simple formula depending upon the well-known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
 | William Smyth - Algebra - 1851 - 272 pages
...of the other two sides ? NOTE. In solving this and other similar questions, it will be recollected that the square of the hypothenuse is equal to the sum of the squares of the other two sides, and the area is equal to one half the product of these sideS. ANS.... | |
 | Edward Deering Mansfield - Education - 1851 - 348 pages
...Pythagoras, in the year five hundred and ninety before Christ, who discovered the fundamental proposition that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Euclid appeared in the year three hundred BC His object was to systematize... | |
 | Jeremiah Day - Geometry - 1851 - 418 pages
...R2= tan x cot. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHF,... | |
 | Charles William Hackley - Trigonometry - 1851 - 524 pages
...last, and a very simple formula depending upon the well known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
 | Edward Deering Mansfield - Education - 1851 - 340 pages
...Pythagoras, in the year five hundred and ninety before Christ, who discovered the fundamental proposition that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Euclid appeared in the year three hundred BC His object was to systematize... | |
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... the square of the hypothenuse is equal to the sum of the squares of the other two sides. 
