 | Edward Olney - Arithmetic - 1879 - 392 pages
...quotient to the root, and add it to the trial divisor, thus forming the True Divisor. Multiply the true divisor by the last root figure, subtract the product...dividend, and to the remainder annex the next period. IV. Repeat the process described in the last paragraph till the work is complete. When any trial divisor... | |
 | Edward Olney - Arithmetic - 1880 - 236 pages
...the trial divisor, thus forming the True Dhisor. Multiply the true divisor by the last root Jigure, subtract the product from the dividend, and to the -remainder annex the next period. IV. Repeat the process described in the last paragraph till the work is complete. When any trial divisor... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 262 pages
...first left-hand period of the given number. Subtract this product from this first left-hand period, and to the remainder annex the next period for a new dividend. Add the figure of the root just found to the amount in the first column, multiply the sum by the same... | |
 | Samuel Mecutchen - Arithmetic - 1880 - 292 pages
...first left-hand period of the given number. Subtract this product from this first left-hand period, and to the remainder annex the next period for a new dividend. Add the figure of the root just found to the amount in the first column, multiply the sum by the same... | |
 | H. Bryant - 1881 - 574 pages
...figure, and add the product to the trial divisor; the sum mil be the true divisor. Multiply the true divisor by the last root figure, subtract the product...remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column 1st ; then add the square of the... | |
 | Henry Bartlett Maglathlin, Benjamin Greenleaf - Arithmetic - 1831 - 386 pages
...three times the product and the square of the last root figure to the trial divisor for a complete divisor. Multiply the complete divisor by the last...product from the dividend, and to the remainder annex a new period. Form a second trial divisor, and proceed as before until all the periods have been used.... | |
 | Alexander Ingram - 1881 - 192 pages
...partial divisor and to the last figure of the root ; then multiply the divisor thus completed by this figure, subtract the product from the dividend, and...remainder annex the next period for a new dividend. 4. Add the last figure of the root to the last complete divisor for a new partial divisor, and proceed... | |
 | William James Milne - Algebra - 1881 - 360 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
 | A. Melrose - 1881 - 314 pages
...root and on the right of the divisor ; then multiply the divisor thus completed by this figure, and subtract the product from the dividend, and to the remainder annex the neit period for a new dividend. To the completed divisor add the figure last placed in the root, for... | |
 | Edward Olney - Algebra - 1881 - 504 pages
...write it as the laghcst order in the root. Subtract the square of this figure from the period used, and to the remainder annex the next period for a new dividend. III. Double the root already found for a Trial Divisor, by which divide the new dividend, rejecting... | |
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Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
