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" Let ABCD, ABEF, be two parallelograms, and ABC, ABF, two triangles, standing on the same base AB, and between the same parallels AB, DE ; then will the parallelogram ABCD be equal to the parallelogram ABEF, and the triangle ABC equal to the triangle ABF. "
The Mechanic's Calculator: Comprehending Principles - Page 56
by William Grier - 1836 - 344 pages
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Elements of Plane and Solid Geometry: And of Plane and Spherical ...

Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...between the same parallels, are equal to each other. Let ABCD, ABEF, be two parallelograms, and ABC, ABF, two triangles, standing on the same base, AB, and between the same parallels AI5, DE ; then will the parallel ogram ABCD be equal to the parallelogram ABEF, and the triangle ABC...
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A First Course of Geometry

130 pages
...Parallelograms on the same base and between the same parallels are equivalent. Let ABCD, ABEF be parallelograms on the same base AB and between the same parallels AB, DE ; to prove that the ||ms ABCD, ABEF are equivalent. In the As ADF, BCE, AD=BC, i.ADF = corr. /-BCE,...
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The Elements of Plane Geometry

Euclid - 1845 - 336 pages
...fig. ABED - A BCE ; .'. || m ABEF = || m ABCD. DEPQ 6 EXERCISES 102. 1. ABCD, ABEF are parallelograms on the same base AB and between the same parallels AB, DE, and the sides BC, AF intersect in G; show that the quadrilaterals AGCD, BGFE are equivalent. 2. ABCD,...
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