 | Encyclopedias and dictionaries - 1920 - 898 pages
...may be and are called opposite. By inspecting the first half of the preceding table it appears that the sine of any middle part is equal to the product of the cosines of its opposite parts, and, from the second half, that the sine of a middle part is the product of the... | |
 | James Atkins Bullard, Arthur Kiernan - Trigonometry - 1922 - 252 pages
...obtained from the following rules given by Napier: In a right spherical triangle, 1. The sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a middle part is equal to the product of the tangents of the adjacent parts. (61) The... | |
 | Andrew Wheeler Phillips, Wendell Melville Strong - Trigonometry - 1926 - 340 pages
...the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 84:. In the right spherical triangles considered in this work, each side is taken less than a semicircumference,... | |
 | David Raymond Curtiss, Elton James Moulton - Trigonometry - 1927 - 396 pages
...product of the tangents of the adjacent parts. (The " tan-adj." rule.) 2. The sine of any circular part is equal to the product of the cosines of the opposite parts. (The " cos-opp." rule.) To illustrate these rules, let us use the appropriate one to obtain a formula... | |
 | Howard Whitley Eves - History - 1983 - 292 pages
...1. The sine of any middle part is equal to the product of the cosines of the two opposite parts. 2. The sine of any middle part is equal to the product of the tangents of the two adjacent parts. (a) By applying each of the above rules to each of the circular... | |
 | Bruno Pattan - Technology & Engineering - 1993 - 420 pages
...are not contiguous to it, or opposite to it. NAPIER'S Rule 1 : The sine of any middle part in circle is equal to the product of the cosines of the opposite parts. eg: 1. sin b or 2. sin A" or cos A or A cos c cos B • cos(90-c) cos(90-B) sin c sin B arcsjn sin... | |
 | Mathematicians - 1915 - 390 pages
...= cot A cot B, that is sin c = tan A tan B. This proves Napier's Theorem: The sine of any circular part is equal to the product of the cosines of the opposite parts and to the product of tangents of the adjacent parts. 1 Bulletin of the American Mathematical Society,... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
