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" If two sides of a triangle are unequal, the angles opposite are unequal, and the greater angle is opposite the greater side. "
Entrance Examinations in Mathematics, 1884 to 1898 [with Supplements to 1900] - Page 33
by Yale University - 1898
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Plane and Solid Geometry

Fletcher Durell - Geometry - 1911 - 553 pages
...point H, it may be shown that /.ACH (= /BCD) is greater than /BAC. QED PROPOSITION XIV. THEOREM 104* If two sides of a triangle are unequal, the angles...and the greater angle is opposite the greater side B Given the side EG > side AB in the A ABO. To prove /.BAC greater than Z C. Proof. On the side BC...
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Plane and Solid Geometry

Isaac Newton Failor - Geometry - 1906 - 440 pages
...respectively to the hypotenuse and an acute Z of the other." § 168 QED 44 PROPOSITION XXII. THEOREM 179 If two sides of a triangle are unequal, the angles...and the greater angle is opposite the greater side. HYPOTHESIS. In the A ABC, AC is greater than AB. CONCLUSION. Z ABC is greater than Z C. PROOF On AC...
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Plane and Solid Geometry

Isaac Newton Failor - Geometry - 1906 - 431 pages
...respectively to the hypotenuse and an acute Z of the other." §168 QED PROPOSITION XXII. THEOREM 179 If two sides of a triangle are unequal, the angles...and the greater angle is opposite the greater side. HYPOTHESIS. In the A ABC, AC is greater than AB. CONCLUSION. Z ABC is greater than Z C. PROOF On AC...
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Plane and Solid Geometry

Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...(?) (770). .'. AR + CR > AB (Ax. 6). That is, AC > AB. QED 772. THEOREM. If two sides of a spherical triangle are unequal, the angles opposite are unequal...and the greater angle is opposite the greater side. To Prove : Z ABC > Z C. Proof : Z ABC is either < ZC or = ZC or > Z C. Continue by method of exclusion...
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Public Documents of Massachusetts, Volume 9

Massachusetts - Massachusetts - 1907 - 1342 pages
...Solve for *. 7- {^ +^=s52} Solve torx and y8' 15 = !2 } Solve for .and,. GEOMETRY. 1. Prove : If the two sides of a triangle are unequal, the angles opposite are unequal, and the greater angle lies opposite the greater side. 2. Prove : The angle between two secants, intersecting without the...
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New Plane and Solid Geometry

Webster Wells - Geometry - 1908 - 336 pages
...From equal A ACD and BCD (Fig. of Prop. XXII), AD = BD, and Z ACD = Z BCD. PROP. XXIII. THEOREM 92. If two sides of a triangle are unequal, the angles opposite are unequal, and the greater angle lies opposite the greater side. Draw AABC, with BC (a) > AC (6). We then have : Given A ABC with side...
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New Plane Geometry

Webster Wells - Geometry, Plane - 1908 - 206 pages
...From equal A ACD and BCD (Fig. of Prop. XXII), AD = BD, and Z ACD = Z BCD. PROP. XXIII. THEOREM 92. If two sides of a triangle are unequal, the angles opposite are unequal, and the greater angle lies opposite the greater side. Draw A ABC, with BG (a) > AC (6). We then have t Given A ABC with side...
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Plane Geometry

Fletcher Durell - Geometry, Plane - 1909 - 360 pages
...it may be shown that /.A CH (— /.BCD) is greater than /.BAC. QED PROPOSITION XIV. THEOREM 104. // two sides of a triangle are unequal, the angles opposite...and the greater angle is opposite the greater side B Given the side BC > side AB in the A ABC. To prove /.BAC greater than Z C. Proof. On the side BC...
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Elements of Plane Geometry

William Herschel Bruce, Claude Carr Cody (Jr.) - Geometry, Modern - 1910 - 286 pages
...this equation, or AC=AD + DB. But AD + DB > AB. § 10 .-.AC>AB. QED PROPOSITION XXII. THEOREM. 127. If two sides of a triangle are unequal, the angles...and the greater angle is opposite the greater side (reciprocal of § 126). Given A ABC, in which AC > BC. To prove %B>%A.. Proof. If £ B is not, > £...
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Secondary-school Mathematics, Book 1

Robert Louis Short, William Harris Elson - Mathematics - 1910 - 202 pages
...Proof. 1. Draw a perpendicular from P to the base. 2. Prove the A formed are equal. THEOREM XX 129. If two sides of a triangle are unequal, the angles opposite are unequal, and the greater angle lies ofiposite the greater side. Draw A DEF making DE > DF. Call DE, f, and DP, e. We now have DM .E...
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