 | Thomas Tate (mathematical master.) - 1848 - 284 pages
...16-8. 8. Required the perpendicular let fall upon the least side in example 2. Ans. 7-66. 4. PROBLEM. To find the area of a trapezium. RULE. Multiply the diagonal by the sum of the perpendiculars let fall upon it, from the opposite angles, and half the product will be the area. Or,... | |
 | Almon Ticknor - Measurement - 1849 - 156 pages
...perpendicular 20 yards ; required the side of the inscribed square. PROBLEM 23. — THE TRAPEZIUM. To find the area of a trapezium. RULE. — Multiply...opposite angles, and half the product will be the area. 1. Required the area of a trapezium whose diagonal AB is 80-5, and the perpendicular C, 24 -5, and... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...- 452 = 2809 - 2025 = 784, and v/784 = 28 = perpendicular BC. To find the area of a trapezium. — Multiply the diagonal by the sum of the two perpendiculars...opposite angles, and half the product will be the area. Required the area of the trapezium BAED, whose diagonal BE is 84, the perpendicular AC 21, and DF 28.... | |
 | Oliver Byrne - Engineering - 1852 - 600 pages
...532 - 452 = 2809 - 2025 = 784, and x/784 = 28 = perpendicular BCTo find the area of a trapezium- — Multiply the diagonal by the sum of the two perpendiculars...opposite angles, and half the product will be the areaRequired the area of the trapezium BAED, whose diagonal BE is 84, the perpendicular AC 21, and... | |
 | Thomas Tate - Geometry - 1855 - 296 pages
...rectangle QRPQ. Application of this Theorem. From this theorem we derive the following rule for finding the area of a trapezium. RULE. Multiply the diagonal by the sum of the perpendiculars let fall upon it, and half the product will be the area of the trapezium. Because oQ... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...-unequal sides. To ascertain the Area of a Trapezium (Fig. 11). RULE. — Multiply the diagonal ac by the sum of the two perpendiculars falling upon it from the opposite angles, and half the product is the area. ,. acxb+d Or, ^r—: — =area. Fig. 11. d EXAMPLE. — The diagonal ac,fig. 11, is 125... | |
 | Anthony Nesbit - Measurement - 1859 - 494 pages
...a trapezium. RULE. Multiply the sum of the two perpendiculars by the diagonal upon which they fall, from the opposite angles, and half the product will be the area. Or, divide the trapezium into two triangles, in the most convenient manner ; and the sum of their areas... | |
 | Alfred Newsom Niblett - 1861 - 204 pages
...quadrilateral figure. RULES. Multiply the sum of the two perpendiculars hy the diagonal upon which they fall, from the opposite angles, and half the product will be the area. Or, divide the trapezium into two triangles, in the most convenient manner, aud the sum of their areas... | |
 | Oliver Byrne - Engineering - 1863 - 600 pages
...- 452 = 2809 - 2025 = 784, and -v/784 = 28 = perpendicular BC. To find the area of a trapezium. — Multiply the diagonal by the sum of the two perpendiculars...opposite angles, and half the product will be the area. Required the area of the trapezium BAED, whose diagonal BE is 84, the perpendicular AC 21, and DF 28.... | |
 | Whiting Griswold - Railroad engineering - 1866 - 144 pages
...sum of the parallel sides by the perpendicular, equals area. To find the area of a trapezium. RULE r. Multiply the diagonal by the sum of the two perpendiculars...it from the opposite angles, and half the product equals area. To find the area of a regular polygon. RULE 8. Multiply one of its sides into half its... | |
| |
To find the area of a trapezium. RULE. — Multiply the diagonal by the sum of the two perpendiculars falling ?;„ upon it from the opposite angles, and divide the product by 2. 
