 | Daniel Parker - Arithmetic - 1828 - 358 pages
...Involve the whole root to the given power, and subtract it uom the given number, as before. 7. Bring down the first figure of the next period to the remainder for a new resolver«! ; find a new divisor as before, ano proceed in like manner until the whole is finished.... | |
 | William Kinne - 1829 - 246 pages
...the given number as before. • 7. Bring down the first figure of the next period to the remaimle/Yor a new dividend, to which find a new divisor, and so on, until the whoie ts finished. EXAMPLES. \. What is the cube root of 53157376 ? 53 : 57376(876 root.... | |
 | William Ruger - Arithmetic - 1832 - 282 pages
...whole ascertained root to the given power; and subtract it from the first and second periods. Bring down the first figure of the next period to the remainder,...for a new dividend; to which, find a new divisor, as before, and so proceed, till the work is finished. NOTE— The roots of the 4th, 6th, 8th, 9th and... | |
 | Zadock Thompson - Arithmetic - 1832 - 182 pages
...root. Involve the whole root to the given, power; subtract it from the given number as before, bring down the first figure of the next period to the remainder for a new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...bring down the first figure of the next period to the remainder for a new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root of 48228544? 48228544 ( 304 363=46656 362 X3=3708 ) 15725 2d div'd. 3643=48228544 2. What... | |
 | Nicolas Pike - Arithmetic - 1832 - 540 pages
...given power, and subtract it from the gicen number, as before. 7. Bring down the first figure of tho next period to the remainder for a new dividend, to which find a new divisor, as belore and, in like manner, proceed till the whole be finished. EXAMPLES. 1st. What is the cube... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...given power, and subtract it from the two left hand periods of the given number. Lastly. — Bring down the first figure of the next period to the remainder, for a new dividend, to which find a new divisor, as before. Thus proceed, till the whole root is extracted. Observe, that when a figure obtained for... | |
 | Charles Potts - Arithmetic - 1835 - 202 pages
...the first and second periods, or from as many periods as you have found periods in the root. Bring down the first figure of the next period to the remainder for a new dividend ; to which find a new divisor as before, and so proceed. NOTE. — The roots of the 4th, 6th, 8th, 9th, and 12th powers may be obtained... | |
 | Stephen Pike - Arithmetic - 1835 - 210 pages
...whoJe ascertained root to the given power, and subtract it from the first and second periods. Bring down the first figure of the next period to the remainder, for a ne\v dividend; to which, find a new divisor, as before; anc! so prrcced. Note. — The roots of the... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...For the square root 2 figures ; for the cube root 3 ; for the 4th foot 4 figures, and so on. 7. Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished ALLIGATION. ALLIGATION" is compounding... | |
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Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished. 
