 | Charles Davies - Geometry - 1854 - 436 pages
...and the area of each rectangle is equal to its base multiplied by its altitude (B. 1v., p. 5). Hence, the sum of these rectangles, or the convex surface of the prism, is equal to (AB +BC+ CD+DE+EA)xAF • that is, to the perimeter of the base of the prism multiplied by the altitude.... | |
 | Charles Davies - Geometry - 1855 - 340 pages
...distance between the parallel planes which form its bases, f THEOREM IThe convex surface of a right prism is equal to the perimeter of its base multiplied by its altitudeLet ABCDE— K be a right prism : then will its convex surface be equal to (AB+BC+ CD+DE+EA)... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the lateral surface of the prism, is equal to the perimeter of its base multiplied by its altitude. Cor. If two right prisms have the same altitude, their lateral surfaces will be to each other as the... | |
 | Elias Loomis - Conic sections - 1858 - 256 pages
...together, from the perimeter of the base of the prism. Therefore, the sum of these parallelograms, or the convex surface of the prism, is equal to the...perimeter of its base, multiplied by its altitude. Cor. If two right prisms have the same altitude, their convex surfaces will be to each other as the... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...together, mate up the perimeter of the prism's base : hence the sum of these rectangles, or the lateral surface of the prism, is equal to the perimeter of its base multiplied by its altitude. Cor. If two right prisms have the same altitude, their lateral surfaces will be to each other as the... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...respectively equal. r BOOK VIII. 187 PROPOSITION I. — THEOREM. 454. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE-K be a right prism; K then will its convex surface be equal to the perimeter of its base,... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...polyedral angles are all equal to each other. PROPOSITION I. — THEOREM.454. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE-K be a right prism; К then will its convex surface be equal p to the perimeter of its base,... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...cylinder. The prism will be inscribed in the convex surface of the cylinder. The convex surface of this prism is equal to the perimeter of its base multiplied by its attitude, AG (Prop. I. Bk. VIII.). Conceive now the arcs subtending the sides of the polygon to be... | |
 | Evan Wilhelm Evans - Geometry - 1862 - 116 pages
...convex surface of the cylinder, and the solidity of the prism with the solidity of the cylinder. But the convex surface of the prism is equal to the perimeter of the base multiplied by the altitude (Theo. VI), and its solidity is equal to the area of the base multiplied... | |
 | Benjamin Greenleaf - Geometry - 1868 - 340 pages
...cylinder. The prism will be inscribed in the convex surface of the cylinder. The convex surface of this prism is equal to the perimeter of its base multiplied by its altitude, AG (Prop. I. Bk. VIII.). Conceive now the arcs subtending the sides of the polv. gon to be continually... | |
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CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude. 
