 | Adrien Marie Legendre - Geometry - 1841 - 288 pages
...the solidity of the cylinder will be * W x If, or * IPH. LEMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (fig. 252),... | |
 | James Bates Thomson - Geometry - 1844 - 268 pages
...base, is also equal to that base. PROPOSITION V. THEOREM. The convex surface of a right prism ACEFHK, is equal to the perimeter of its base multiplied by its altitude AF. For, since the sides of a right prism are K perpendicular to its base ; (Def. 7. 7 ;) all its lateral... | |
 | Nathan Scholfield - 1845 - 894 pages
...Now, the altitudes AF, BG, CH, &c. of the rectangles, are equal to the altitude of the prism. Hence, the sum of these rectangles, or the convex surface of the prism, is equal to (AB+BC+CD+DE+EA)X AF ; that is, to the perimeter of the base of the prism multiplied by its altitude.... | |
 | George Roberts Perkins - Geometry - 1847 - 326 pages
...prism ; their bases AB, BC, CD, &c. taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface...perimeter of its base multiplied by its altitude. Cor. If two right prisms have the same altitude, their convex surfaces will be to each other as the... | |
 | Elias Loomis - Conic sections - 1849 - 252 pages
...together, from the perimeter of the base of the prism. Therefore, the sum of these parallelograms, or the convex surface of the prism, is equal to the...perimeter of its base, multiplied by its altitude. Cor. If two right prisms have the same altitude, their convex surfaces will be to each other as the... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...Now, the altitudes AF, BG, CH, &c. of the rectangles, are equal to the altitude of the prism. Hence, the sum of these rectangles, or the convex surface of the prism, isequalto(AB + BC + CD + DE + EA)x BC AF; that is, to the perimeter of the base of the prism multiplied... | |
 | George Roberts Perkins - Geometry - 1850 - 332 pages
...prism ; their bases AB, BC, CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface...perimeter of its base multiplied by its altitude. Cor. If two right prisms have the same altitude, their convex surfaces will be to each other as the... | |
 | Charles Davies - Geometry - 1850 - 238 pages
...distance between the parallel planes which form its bases. THEOREM I. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABODE— K be a right R prism: then will its convex surface be equal to (AB+BC+ CD+DE+EA) x AF.... | |
 | Charles Davies - Geometry - 1850 - 218 pages
...distance between the parallel planes which form its bases, THEOREM I. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABODE— K be a right J{. prism: then will its convex surface be equal to (AB 4- BC + CD + DE -f... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...rectangle is equal to its base multiplied by ^,. ... , its altitude (B. iv., P. 5). Hence, the sum x of these rectangles, or the convex surface of the prism, is equal to (AB+BC+CD+DE+EA)xAF; that is, to the perimeter of the base of the prism multiplied by the altitude.... | |
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CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude. 
