 | Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...and the side B, C, 12 feet. What is the length of the side A, B? a In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
 | Joseph Denison - Mechanics - 1841 - 210 pages
...circumference of the screw; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) the square of the hypothenuse is equal to the sum of the squares of the base and perpen-dicular ; that is * 2 — A 2 + c 2 ; and extracting the square root... | |
 | Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 503 = 40*+ 30s. [Fig. 8.] 16. Hence, to find the different sides,... | |
 | Joseph Denison - Mechanics - 1841 - 210 pages
...circumference of the screw ; but the triangle klm is a right-angled triangle ; and (by 1 Euclid, 47.) the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; that is *' = A2 + c2 ; and extracting the square root of these... | |
 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...triangles the longest side is usually considered the Base. 15. In every right-angled triangle, — The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 50" = 40" + 30!. [Fig. 8.] 16. Hence, to find the different sides,... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...perpendicular 48 rods, how many acres ? Ans. 7a. 2r. 36 rods. ART. 2. — In every right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the other two sides. 1. Hence, when the legs are given, to find the hypothenuse. RULE. Add... | |
 | William Carus Wilson - 1848 - 978 pages
...heart, the circulation of the blood, and the process of respira10. Prove that in a right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the sides. 11 Prove that if two straight lines intersect one another in a circle, the rectangles... | |
 | English literature - 1846 - 614 pages
...Humeist did not really doubt that Caesar once lived in Rome — that the sun will rise to-morrow — that the square of the hypothenuse is equal to the sum of the squares of the opposite sides. In all these matters man is satisfied to act upon the knowledge arising... | |
 | Anna Cabot Lowell - Geometry - 1846 - 216 pages
...Consequently CDML -f LMEA = square ACED = square AFGB -j- BCKH. That is, in every right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the other two sides. This is called the proposition of Pythagoras, because he first discovered... | |
 | Roswell Chamberlain Smith - Arithmetic - 1847 - 308 pages
...Irregular figure divide it into triangles. A In any right-angled triangle, it has been ascertained, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Thus, in the adjacent figure, 40« = 1600, andSO2 = 900 ; then,-/ 900+1600... | |
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The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302. 
