 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let A BCD be any parallelogram and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD,... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 312 pages
...rectangle? How does the altitude of one ,, _' -F compare with that of the A Jit JJ , other? Principle. — The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...the rectangle? How does the altitude of one ( , j. compare with that of the other? Principle.—The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
 | George Albert Wentworth - Geometry, Solid - 1902 - 248 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 400. The area of a parallelogram is equal to the product of its base by its altitude. 401. Parallelograms having equal bases and equal altitudes are equivalent. 403.... | |
 | American School (Chicago, Ill.) - Engineering - 1903 - 390 pages
...195. Corollary. The area of a square is equal to the square of one of its sides. THEOREn LXIV. Ip6. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be a parallelogram leaving its altitude DF equal to a and its base AD equal to ft. To prove that ABCD... | |
 | George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 496 pages
...wide a road is cut 4 rd. wide. How many acres are cut off for the road? PROPOSITION IV. THEOREM 322. The area of a parallelogram is equal to the product of its base by its altitude. A b BA b B Given the parallelogram ABCD, with base b and altitude a. To prove... | |
 | Walter Burton Ford, Earle Raymond Hedrick - Geometry, Modern - 1913 - 272 pages
...triangles. Find the area of each of these triangles. Ans. 15 sq. in. AREAS [IV, § 186 186. Theorem I. The area of a parallelogram is equal to the product of its base by its altitude. F_ GD G Given the parallelogram ABCD with b its base and a its altitude. To prove... | |
 | George E. Mercer, Mabel Bonsall - Arithmetic - 1914 - 324 pages
...should be given practice in drawing them until the mention of a name calls forth an appropriate drawing. The area of a parallelogram is equal to the product of its base and altitude. The base and altitude must be expressed in units of the same kind. The diagonal of a parallelogram... | |
 | William James Milne - Arithmetic - 1914 - 524 pages
...resulting figure will be a rectangle of the same area, base, and altitude as the BASE parallelogram. The area of a parallelogram is equal to the product of its base and altitude, expressed in like units. ' ' " and Written Exercises Estimate results mentally before solving. Find... | |
 | Edward Rutledge Robbins - Geometry, Plane - 1915 - 282 pages
...times as long as it is wide, how many square yards will the field contain? PROPOSITION IV. THEOREM 359. The area of a parallelogram is equal to the product of its base by its altitude. FD EC Given : O ABCD, with base b and j altitude h. To Prove : Area of ABCD =... | |
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The area of a parallelogram is equal to the product of its base and altitude. 
