 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and an equal altitude.... | |
 | Arthur Schultze - 1901 - 392 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h.... | |
 | Arthur Schultze - 1901 - 260 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...303. (6) The area of any rectangle is equal to the product of its base and its altitude. § 304. (7) The area of a parallelogram is equal to the product of its base and its altitude. § 305. (8) The area of a square is equal to the square of any one of its sides. § 307.... | |
 | Arthur Schultze - 1901 - 260 pages
...rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. TTie area of a parallelogram is equal to the product of its base and its altitude. A Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To frnn.e... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...rectangle is 360 square inches, and its base ia 4 yds. Find the altitude. PROPOSITION IV. THEOREM 341. TJie area of a parallelogram is equal to the product of its base and its altitude. Hyp. ABCD is a parallelogram, having the base AB — b, and the altitude BE = h. To prove... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE =... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...Similarly the second power of a number is called the square of the number. PROPOSITION V. — THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Given. — Let ABCD be any parallelogram, AB its base, and BE its altitude. To... | |
 | Samuel Wesley Baird - Arithmetic - 1901 - 174 pages
...Find the cost of cementing a cellar bottom 54 ft. .long and 18| ft. wide, at 62|/ a square yard. Since the area of a parallelogram is equal to the product of its length and breadth, either side will equal the area divided by the other side. 6. A blackboard has... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. K a Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE... | |
| |
The area of a parallelogram is equal to the product of its base and altitude. 
