| Albert Newton Raub - Arithmetic - 1877 - 348 pages
...are the rules for the measurements of triangles: It was proved in Denominate Numbers (Art. 107) that the area of a parallelogram is equal to the product of its base and altitude, and since a triangle is half a parallelogram, we derive the following RULE. 1. To find the area of... | |
| George Albert Wentworth - Geometry - 1877 - 416 pages
...equal to the unit of measure ; and the area of the figure equals 7X4. PROPOSITION IV. THEOREM. 321. The area of a parallelogram is equal to the product of its base and altitude. BE CFB CE F D AD Let AE FD be a parallelogram, AD its base, and С D its altitude. We are to prove... | |
| William Guy Peck - Arithmetic - 1877 - 430 pages
...its altitude ? Ans. 16 ft. AREA OF A PARALLELOGRAM. 285. It is shown in Geometry (B. 4, P. 3), that the area of a parallelogram is equal to the product of its base and altitude; that is, Area of parallelogram = Base x Altitude. EXAM PLE S. 1. The base of a parallelogram is 14... | |
| William Chauvenet - Geometry - 1877 - 396 pages
...is measured by the product of the numerical measures of the lines. PROPOSITION IV.— THEOREM. 10. The area of a parallelogram is equal to the product of its bass and altitude. Let AB CD be a parallelogram, k the * D numerical measure of its base AB, h that... | |
| William Frothingham Bradbury - Arithmetic - 1879 - 392 pages
...of a parallelogram is the perpendicular distance from the opposite side to the base ; as К N. 47L The area of a parallelogram is equal to the product of its base and altitude. NOTE. For the Rectangle see Arts. 197-201. 7. What is the area of a parallelogram whose base is 25... | |
| William Frothingham Bradbury - Geometry - 1880 - 260 pages
...will evidently contain 5X4, or 20, of these squares; that is, its area = 5 X 4 = 20. THEOREM XVI. 43. The area of a parallelogram is equal to the product of its base and altitude. lelogram ABCD ; then the area of j 7 ~7 Let DF be the altitude of the paral- EBFC / At A draw the perpendicular... | |
| George Anthony Hill - Geometry - 1880 - 332 pages
...positions shown in the figure. Corollaries. — I. By combining this theorem with § 128, we see that the area of a parallelogram is equal to the product of its base by its altitude. 2. All parallelograms having equal bases and equal altitudes are equivalent.... | |
| George Albert Wentworth - 1881 - 266 pages
...; and the area of the figure equals 7X4. ! : i • Î : ! 1 ._ ! | ! PROPOSITION IV. THEOREM. 321. The area of a parallelogram is equal to the product of its base and altitude, BE С FB СE F D AD Let AE FD be a parallelogram, AD its base, and С D its altitude. We are to prove... | |
| Education - 1890 - 384 pages
...x, equidistant from two given points, and also equidistant from two given parallel lines. 8. Prove: The area of a parallelogram is equal to the product of its base and altitude. 5). The base of a triangle is UK) varas .the altitude is 50 varas. What is its area. 10. The diameter... | |
| F. B. Stevens - Examinations - 1884 - 202 pages
...a triangle divides the opposite side into segments whi^h are proportional to the adjacent sides. 3. The area of a parallelogram is equal to the product of its base and altitude. 4. How do you find the area of a trapezoid ? The areas of similar polygons are to each other in what... | |
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