| W. H. Spiller - Algebra - 1835 - 210 pages
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as the square of the hypothenuse is equal to the sum of the squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
| Abel Flint - Geometry - 1835 - 368 pages
...without finding the angles ; according to the following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE SQUARES OF THE TWO LEGS. HENCE, THE SQUARE OF THE GIVEN LEG BEING SUBTRACTED FROM THE SQUARE OF THE... | |
| Madras literary society - 1837 - 996 pages
...which AE is the other kg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, the square of the hypothenuse is equal to the sum of the squares of the other two sides; in the right angle triangle AEB,— BE8 -f- AE JL AB* : but as BE,... | |
| Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
| Charles Davies - Navigation - 1837 - 342 pages
...by either of the four last cases : or, if two of the sides are given, by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
| Alexander Jamieson - Fluid mechanics - 1837 - 516 pages
...sides DH and CE ; that is, tf=\(xy). Consequently, by the property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, we shall have (i,y =*• + «*—y)'; and by extracting the... | |
| Charles William Hackley - Trigonometry - 1838 - 338 pages
...and a very simple formula depending upon the well known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
| Jeremiah Day - Geometry - 1838 - 416 pages
...the third side may be found, without the aid of the trigonometrical tables, by the proposition, that the square of the hypothenuse is equal to the sum of the squares of the two perpendicular sides. (Euc. 47. L) If the legs be given, extracting the square root... | |
| Technology - 1838 - 510 pages
...equal, and together forming an inscribed square to the circle AB C D. Then, as in right angle triangles, the square of the hypothenuse is equal to the sum of the squares of the other two sides, in the right angle triangle AEB, B Е 2 +Л E 2 = AB 2 : but as BE,... | |
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