 | James Bates Thomson - Algebra - 1844 - 272 pages
...What is the value of each horse 1 Prob. 52. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. If x, y and z, be three of the parts, the fourth will be 90 — x — y — z.... | |
 | Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...divided into 4 such parts, that if to the first part 2 be added, from the second part 2 be subtracted, the third multiplied by 2, and the fourth divided by 2, the several results will be equal. Ans., the first, 8 ; second, 12 ; third, 5 j and the fourth, 20. 7.... | |
 | Charles Davies - Algebra - 1845 - 382 pages
...what was its value? Ans. £4 16*. 17. To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the...multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient so obtained, will be all equal to each other. Ans. The parts... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...all equal to each other. Ans. 8, 12, and 16. 10. Divide 90 into four such parts, that if the first be increased by 2 ; the second diminished by 2 ; the...multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient so obtained, may be all equal to each other. Ans. 18, 22, 10,... | |
 | Charles William Hackley - Algebra - 1846 - 542 pages
...remaining; what had he at first? Ans. 20*. (35) To divide the number 90 into 4 such parts that if the first be increased by 2, the second diminished by 2, the...multiplied by 2> and the fourth divided by 2, the sum, difference, product, and quotient shall be all equal to each other ? Ans. The parts are 18, 22,... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...~ of the second. a — oa — o Prob. 45. Divide the number 45 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2 shall all be equal. In solving examples of this kind, several unknown quantities are usually introduced,... | |
 | James Bates Thomson - Algebra - 1846 - 276 pages
...What is the value of each horse 1 Prob. 52. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth dividedby 2, shall all be equal. If a1, y and z, be three of the parts, the fourth will be 90 — x... | |
 | John Hunter (of Uxbridge.) - 1847 - 266 pages
...man's age on his weddingday, &c. Ans. 9. Divide the number 90 into four §uch parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all yield the same result Sol. As 2 is added to and subtracted from the first and second parts,... | |
 | Jeremiah Day - Algebra - 1847 - 358 pages
...each horse 1 Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. If x, y, and z, be three of the parts, the fourth will be 90 - x - y - z. And by... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...7. Ans. 49 and 42. 69. It is required to divide the number 72 into 4 such parts, that if the first be increased by 2, the second diminished by 2, the...multiplied by 2, and the fourth divided by 2, the sum, the difference, the product, and the quotient shall all be equal. Ans. 14, 18, 8, and 32. Let... | |
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To divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied... 
