 | Arthur Schultze - 1901 - 392 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h.... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...rectangle is 360 square inches, and its base ia 4 yds. Find the altitude. PROPOSITION IV. THEOREM 341. TJie area of a parallelogram is equal to the product of its base and its altitude. Hyp. ABCD is a parallelogram, having the base AB — b, and the altitude BE = h. To prove... | |
 | Arthur Schultze - 1901 - 260 pages
...rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. TTie area of a parallelogram is equal to the product of its base and its altitude. A Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To frnn.e... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY I. The area of any parallelogram is equal to the product of its base and altitude. Let A BCD be any parallelogram and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD,... | |
 | Samuel Wesley Baird - Arithmetic - 1901 - 174 pages
...Find the cost of cementing a cellar bottom 54 ft. .long and 18| ft. wide, at 62|/ a square yard. Since the area of a parallelogram is equal to the product of its length and breadth, either side will equal the area divided by the other side. 6. A blackboard has... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. K a Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE =... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...Similarly the second power of a number is called the square of the number. PROPOSITION V. — THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Given. — Let ABCD be any parallelogram, AB its base, and BE its altitude. To... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 312 pages
...rectangle? How does the altitude of one ,, _' -F compare with that of the A Jit JJ , other? Principle. — The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 288 pages
...the rectangle? How does the altitude of one ( , j. compare with that of the other? Principle.—The area of a parallelogram is equal to the product of its base and altitude. PROBLEMS 1. Find the area of a parallelogram whose base is 16 rd. and whose altitude is 8 rd. 2. What... | |
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The area of a parallelogram is equal to the product of its base and altitude. Let... 
