 Multiply as in whole numbers, and point off as many decimal places in the product as there are in both multiplicand and multiplier. DIVISION. Divide as in whole numbers, and point off...  The Elements of Algebra ... - Page 19by James Wood - 1825 - 305 pagesFull view - About this book
 | John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1893 - 316 pages
...as many .2544 decimal places as there are in both factors. 18. Multiply .253 by .35. ,,-.-, Multiply as in whole numbers, and point off as many decimal places in the product as there are in both multiplicand and mul1265 tiplier. If there are not enough figures in 759 the product to fill the... | |
 | Edward Brooks - Arithmetic - 1893 - 228 pages
...P = To-5 X 3 -*& — 3 - 45 - From cither of these solutions we derive the following RULK.—Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. NOTE 1.—When... | |
 | Henry B. Maglathlin - 1894 - 370 pages
...places in the product is equal to the number of decimal places in both of the factors. BULB. Multiply as in whole numbers, and point off as many decimal places in the product as there are decimal places in the multiplicand and multiplier, supplying the deficiency, if any, by prefixing ciphers.... | |
 | George Washington Hull - Arithmetic - 1895 - 408 pages
...the result is 5904 thousandths, or 5.904. 2D. 24.6 x .24 = -\V- x TVs = fflt = 5.904. RULE. Multiply as in whole numbers, and point off as many decimal places in the product as there are in both factors. Prefix ciphers to the product if it does not contain the required number of figures.... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...product directly under tlie figure of the multiplier which produces it. 3. Add these partial products and point off as many decimal places in the product as there are in the multiplicand, and the result will be the true product. 62. PROOF. Multiply the multiplier by the multiplicand,... | |
 | John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1895 - 330 pages
...contains as many ."2544 decimal places as there are in both factors. 18. Multiply .253 by .35. Multiply as in whole numbers, and point off as many decimal places in the product .oi> as there are in both multiplicand and mul1265 tiplier. If there are not enough figures in 759... | |
 | Edward Brooks - Arithmetic - 1895 - 248 pages
...decimal places in the quotient, therefore the quotient is 3.45. Hence the following method : Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor. 1. When... | |
 | George Washington Hull - Arithmetic - 1895 - 404 pages
....34 = 2176 + JL « 2H6 x 100 2176 1000 2176_ 34 34 100 . 2176 x JlOO 1000 34 10 x = 6.4. RULE. Divide as in whole numbers, and point off as many decimal places in the quotient as those in the dividend exceed those in the divisor. 6. .36 -t 9. 7. .42 •4- 6. 8. .64... | |
 | Bothwell Graham - Arithmetic - 1895 - 240 pages
...Multiply the numerators together as though they were integers. II. To find the denominator of the product. Point off as many decimal places in the product as there are decimal places in both factors, prefixing when necessary zeros to supply the deficiency. 2. Divide... | |
 | John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1895 - 324 pages
...as there are in both factors. 18. Multiply .253 by .35. oco Multiply as in whole numbers, and paint off as many decimal places in the product ."" as there are in both multiplicand and mul1265 tiplier. If there are not enough figures in 759 the product to fill the... | |
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