 | Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...the deficiency by prefixing ciphers. NOTE. — To multiply a decimal by 10, 100, 1000, &c., remove the decimal point as many places to the right as there are ciphers in the multiplier ; and if there be not places enough in the number, annex ciphers. Thus, 1.25 X 10 = 12.5; and 1.7 X... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1871 - 384 pages
...given denomination. Since the multiplier is always 10, 100, 1000, &c., the operation is performed by removing the decimal point as many places to the right as there are ciphers ia the multiplier, annexing ciphers •when necessary. EXAMPLES FOR PRACTICE. 1. Reduce "M 32.58 to... | |
 | Henry Bartlett Maglathlin - 1872 - 338 pages
...in 1 dollar 100 times 10 mills, or 1000 mills, and in 8 dollars 8 times 1000 mills, or 8000 mills. RULE. To reduce cents to mills, multiply by 10 ; dollars...as there are ciphers in the multiplier (Art. 30). Examples. 4. In $162 how many mills ? Ans. 1G2000 mills. 5. In $1.62 how many cents ? ' Ans. 162 cents.... | |
 | Joseph Ray - Arithmetic - 1866 - 212 pages
...Since the multiplier is always 10, 100, 1000, etc., the operation may be performed by removing the point as many places to the right as there are ciphers in the multiplier. EXAMPLE. — How many kilometers in 36429 M.? SOLUTION. — Since 1000 meters = 1 kilometer. 36429... | |
 | Daniel O'Sullivan - 1872 - 382 pages
...(i.) when the multiplier is either 10 or a power of 10 : Remove the decimal point of the multiplicand as many places to the right as there are ciphers in the multiplier. (2.) When the multiplier is not a power of 10, and does not exceed 12 : Multiply the units' figure... | |
 | George Payn Quackenbos - Arithmetic - 1872 - 350 pages
...266 776 product. 342 2gl 185. To multiply a decimal A™. 3.686 3.686 by 10, 100, 1000, &c., remove the decimal point as many places to the right as there are naughts in the multiplier. If there are not figures enough for this, annex naughts to supply the deficiency.... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1873 - 362 pages
...in 1 dollar 100 times 10 mills, or 1000 mills, and. in 8 dollars- 8 rtmea 1000 mWs, or 8000 mi/fa. RULE. To reduce cents to mills, multiply by 10 ; dollars...many cents ? Ans. 162 cents. 6. In $31 how many cents ? 7. In $6.008 how many mills ? Ans. 6008 mills. 8. In 87 cents how many mills ? Ans. 870 mills. 9.... | |
 | Emerson Elbridge White - Arithmetic - 1870 - 348 pages
...the deficiency by prefixing decimal ciphers. 2. To multiply a decimal by 10, 100, 1000, etc., Remove the decimal point as many places to the right as there are ciphers in the multiplier. NOTE. — If there be not enough decimal places in the product, supply the deficiency by annexing ciphers.... | |
 | George Payn Quackenbos - Arithmetic - 1874 - 444 pages
...multiply a decimal, or a mixed number consisting of integer and decimal, by 10, 100, 1000, etc., remove the decimal point as many places to the right as there are ciphers in the multiplier. If there are not figures enough for this, annex ciphers to supply the deficiency. Show the reason for... | |
 | Henry Bartlett Maglathlin - Arithmetic - 1875 - 346 pages
...removing the dollar mark and the decimal point. For, multiplying by 1 0, 1 00, etc., has the same eflect as removing the decimal point as many places to the...as there are ciphers in the multiplier (Art. 30). Examples. 4. In $162 how many mills ? Ana. 162000 mills. 5. In $1.62 how many cents ? Ans. 162 cents.... | |
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To multiply a decimal by 10, 100, 1000, &c., remove the decimal point as many places to the right as there are ciphers in the multiplier ; and if there be not places enough in the number, annex ciphers. 
