...Problem I. that the number of terms is one more than the number of differences ; therefore 8 -J- 1 = 9, the number of terms. RULE. — Divide the difference of the extremes by the common differen«e, and the quotient increased by one will be the number of terms required. 9. If the extremes...

...at what rate did he increase his speed ? Ans. 2 mi. per day. IV. The two extremes, and tJie common difference being given, to find the number of terms. RULE. — Divide the difference between the two extremes by the common difference, and to the quotient add 1 for the required number...

...the extremes by the number of terms, less one. (3). The first term, common difference, and last term being given to find the number of terms. RULE. —...difference of the extremes by the common difference, and add 1 to the quotient. (4). The first term, number of terms, and last term being given to find...

...what is the common difference of their ages? CASE III. When the extremes and common difference are given, to find the number of terms. RULE.— Divide...difference of the extremes by the common difference, and add 1 to the quotient for the number of terms. 8. If the extremes of an arithmetical series be...

...the common difference. 29— 3=26; and 26-4-13=2. Ans. Given the common difference and the extremes, to find the number of terms. Rule. — Divide the...difference of the extremes by the common difference, and to the quotient add one. Example. — The first term of an arithmetical progression is 11, the...