| Charles Davies - Algebra - 1848 - 300 pages
...— x+— y+— z=1 -5 4- O to find x, y Ans. x=12, y = 20, i;=30. 4. Divide the number 90 into four such parts that the first increased by 2, the second...third multiplied by 2, and the fourth divided by 2, shall be equal to each other. This question may be easily solved by introducing a new unknown quantity.... | |
| Joseph Ray - Algebra - 1848 - 250 pages
...Ans. 49 and 42. 69. It is required to divide the number 72 into 4 such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, the difference, the product, and the quotient shall all be equal. Ans. 14, 18, 8, and 32.... | |
| John Bonnycastle - 1848 - 334 pages
...Ans. 300. 26. It is required to divide the number 90 into four such parts, that if the first part he increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient, shall be all equal. Ans. The parts are 18, 22, 10, and... | |
| Charles Davies - Algebra - 1851 - 300 pages
...4 5 to find x, y and 2. Ans. x=12, y=20, x=30 4. Divide the number 90 into four such parts that th< first increased by 2, the second diminished by 2,...third multiplied by 2, and the fourth divided by 2, shall be equal to each other. This question may be easily solved by introducing a new unknown quantity.... | |
| 1851 - 382 pages
...f_L-V8j> V my'/ - „ . \x+y/ . „ . 6. Divide the number 90 into four such parts, that if the first is increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product and quo tient may be equal, . , , . Geometry and Mensuration. 1. Given... | |
| John Bonnycastle - Algebra - 1851 - 288 pages
...Ans. 300. 32. It is required to divide the number 90 into four such parts, that if the first part be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient, shall be all equal?' Ans. The parts are 18, 22, 10, and... | |
| John Radford Young - 1851 - 266 pages
...ounces of pewter in a pound of it. (17) Divide the number 90 into four parts, such that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the results may all be equal to one another. (1 8) A number consists of three digits of which the difference... | |
| Joseph Ray - Algebra - 1848 - 250 pages
...Ans. 49 and 42. 69. It is required to divide the number 72 into 4 such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, tha difference, the product, and the quotient shall all bo equal. Ans. 14, 18, 8, and 32.... | |
| William Somerville Orr - Science - 1854 - 534 pages
...the value of the unreduced 40 quarts. 248-| 19. Divide 90 into four parts, such, that if the first be increased by * 2, the second diminished by 2, the third multiplied by 2, and the fourth 280s. divided by 2, the results may all be equal. Let the first part be x — 2 : this, increased by... | |
| Popular educator - 1854 - 922 pages
...-19. Divide the number 90 into 4 such pnrts, that the first is increased by 2, the second diminMed by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. Ans. 18, 22, 10, and 40. Prob. 50. Find three numbers, such that the first with... | |
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