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" It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. "
A Course of Mathematics: For the Use of Academies, as Well as Private ... - Page 248
by Charles Hutton - 1831
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An Elementary Algebra for Schools and Academies

Joseph W. Wilson - Algebra - 1873 - 268 pages
...sums will be in the ratio of 5 to 6. What are the numbers ? Ans. 15 and 20. 29. Divide the number 36 into two such parts that the quotient of the greater part divided by 6 shall be to the quotient of the less divided by 30 as 25 is to 1. Ans. 30 and 6. 30. Find two numbers...
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New Elementary Algebra

Horatio Nelson Robinson - Algebra - 1874 - 312 pages
...two such parts, that the sum of the squares of those parts shall be b. Am. (a v^) — a2). 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers...
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Key to Davies' Bourdon: With Many Additional Examples, Illustrating the ...

Charles Davies - Algebra - 1879 - 277 pages
...2304. whence, by the rule, ж = 50уТ96~=50 14; hence, x = 64, x = 36, and у = 36, у = 64. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Let x and у denote the parts. From the conditions...
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New Elementary Algebra: Containing the Rudiments of the Science for Schools ...

Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...30. 21. It is required to divide the number 14 into two such parts, that the quotient of the greater divided by the less, may be to the quotient of the less divided by the greater, as 16 : 9. Ans. The parts are 8 and 6. 22. What two numbers are those whose...
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The Normal Teacher, Volume 3

Education - 1880
...less. *It is required to divide the number 14 into two such parts, that the quotient of the greater divided by the less, may be to the quotient of the less divided by the greater, as 16 : 9. JE WHITE. 3. [Vol. Ill, No. I, Q. i, p. 21.] I have some corn worth...
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Annual Report

1886
...5. Find the value of a; in Tij (2x _ 8) — J (3a; — 2) + 8& — J (4a; — 3 | = 0. 6. Divide 91 into two such parts that the quotient of the greater part, divided by the difference between the parts, may be 7. GEOMETRY. First Division will take 1, 2, 4, 5. Second Division...
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Wentworth and Hill's Examination Manuals: Algebra, Issue 2

George Albert Wentworth - Algebra - 1884 - 168 pages
...Divide ж2-МУ + Уbуж4 + 3 , 3V — 2ж ca о , 5. Solve 2ж — ^4 — = 74 5 6. Divide 91 into two such parts that the quotient of the greater part divided by the difference between the parts may be 7. 7. Extract the square root of 16ж4 — 32 a? + 24 a;2 — 8x+l....
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Exercises in Algebra, Parts 1-2

George Albert Wentworth - 1897 - 406 pages
...4. Divide ж3 + ж4y* + y3 by x4 + я?y1 + y*. кол о У+3 5. Solve 2ж — !L—- 6. Divide 91 into two such parts that the quotient of the greater part divided by the difference between the parts may be 7. 7. Extract the square root of 16ж4-32ж2 + 24ж2-8ж+ 1. 18....
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Entrance Examinations in Mathematics, 1884 to 1898 [with Supplements to 1900]

Yale University - 1898 - 212 pages
...the simultaneous equations x -f- 2y + 27. = n, 2x -f у + z = у, зх + 4y + z = 14. 4. Divide 91 into two such parts that the quotient of the greater part divided by the difference between the parts may be 7. 5. Expand (i — 2x:* )* by the binomial formula. 6. Simplify...
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Yale University Entrance Examinations in Mathematics: 1884 to 1898

Mathematics - 1898 - 208 pages
...the simultaneous equations x -|- 2y + 2z = n, 2x + y -f- z = 7, 3x -+- 4y -f- z = 14. 4. Divide 91 into two such parts that the quotient of the greater part divided by the difference between the parts may be 7. 5. Expand (1 — 2x )4 by the binomial formula. 6. Simplify...
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