Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 261by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| Edward Olney - Arithmetic - 1879 - 404 pages
...the tria' divisor, thus forming the True Dijisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period. IV. Repeat the process described in the last paragraph till the work is complete. When any trial divisor... | |
| Shelton Palmer Sanford - Algebra - 1879 - 348 pages
...trial divisor to form• the complete divisor. III. Multiply the complete divisor by the second term of the root, subtract the product from the dividend, and to the remainder bring down as many terms as may be necessary for a new dividend. IV. Double the terms of the root already... | |
| George E. Seymour - Arithmetic - 1880 - 332 pages
...annexing the square of the last figure of the root. VII. Multiply the complete divisor thus found, by the last figure of the root, subtract the product from the dividend, and bring down the next period. VIII. Square the root noio found and multiply by three for a trial divisor.... | |
| William James Milne - Algebra - 1881 - 360 pages
...trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend. Proceed in this manner until all the periods have been used thus. The result will... | |
| A. Melrose - 1881 - 314 pages
...root and on the right of the divisor ; then multiply the divisor thus completed by this figure, and subtract the product from the dividend, and to the remainder annex the neit period for a new dividend. To the completed divisor add the figure last placed in the root, for... | |
| Arithmetic - 1882 - 392 pages
...the trial divisor, thus forming the complete divisor. 2. Multiply the complete divisor by the second figure of the root; subtract the product from the...dividend; and to the remainder annex the next period for a dividend. IV. To find the succeeding figures of the root:— Proceed with t/ie second, and with each... | |
| James Gray - Arithmetic - 1883 - 154 pages
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in the root : subtract the product from the dividend, and to the remainder bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
| James William Nicholson - Arithmetic - 1885 - 348 pages
...it to the trial divisor, to form the complete divisor. Multiply the complete divisor by the second figure of the root ; subtract the product from the...dividend, and to the remainder annex the next period for a dividend. Proceed with the second, and with each succeeding dividend, in the same manner as with the... | |
| George Albert Wentworth - Arithmetic - 1889 - 676 pages
...root. To this partial divisor add the second part of the root for a complete divisor. Multiply this complete divisor by the last figure of the root, subtract...the dividend, and to the remainder annex the next group for a new dividend. Proceed in this manner until all the groups have been thus annexed. The result... | |
| James William Nicholson - Arithmetic - 1889 - 408 pages
...to the trial divisor, to form the complete divisor. IV. Afultiply the complete divisor by the second figure of the root; subtract the product from the...dividend, and to the remainder annex the next period for a dividend. V. Proceed with the second, and with each succeeding dividend, in the same manner as with... | |
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