| Eli Todd Tappan - Geometry - 1868 - 444 pages
...next to it are the adjacent parts, and the remaining two are the opposite parts. Napier's rule is : **The sine of the middle part is equal to the product of the tangents of the** adjacent parts, also to the product of the cosines of the opposite parts. The words sine and middle... | |
| Sir Norman Lockyer - Electronic journals - 1872 - 540 pages
...included in the two rules known as Napier's rules, that the sine of the middle (that is, of any chosen) **part is equal to the product of the tangents of the two** adjacents, as well as to the product of the cosines of the two opposite parts. As a rule to assist... | |
| William Chauvenet - Trigonometry - 1871 - 268 pages
...considered, the two sides including it are regarded as adjacent parts. The rules are : I. The tine **of the middle part is equal to the product of the tangents of the** adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite... | |
| Henry W. Jeans - 1873 - 272 pages
...selected is called the middle part. Eule A will apply to the former case, Eule B to the latter. EULE A. **The sine, of the middle part is equal to the product of the tangents of the two** parts adjacent to it. * The complement of an angle is what it wants of 90° ; thus, in the , P right-angled... | |
| Aaron Schuyler - Measurement - 1873 - 508 pages
...90°— h, b. 9. 90°— h, 90°— P, b. 10. 90°— P, 90°— B, p. 126. Napier's Principles. 1. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts. Draw BD and DE, respectively perpendicular to OH and OP, and draw BE. BDE is a right... | |
| Henry William Jeans - 1873 - 292 pages
...substituted for cos. со. A ; cos. A for sin. со. A ; cot. A for tan. со. A, to. (See Part II.) EULE B. **The sine of the middle part is equal to the product of the** cosines -of the two parts opposite to, or separated from it.* Having written down the equation according... | |
| Aaron Schuyler - Measurement - 1864 - 512 pages
...OZi = OE= cos A = sin (90°— A). . • . (5) sin (900— A) = tan (90°— Б) tan (90°— P). 2. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. OE=cos EOD X OD, or cos A = cos b cos p. ... (6) sin (90°— A) = cos... | |
| Aaron Schuyler - Navigation - 1873 - 536 pages
...cosEODxOD=OE=coa h = sin (90°— A). . • . (5) sin (90°— A) = tan (90°— B) tan (90°— P). 2. **Sine of the middle part is equal to the product of the** co-sines of the opposite parts. = cos EOD X OD, or cos h = cos 6 cos p. ... (6) sin (90°— A) = cos... | |
| Aaron Schuyler - Measurement - 1875 - 284 pages
...90°— Л, b. 9. 90°— A, 90'— P, b. 10. 90°— P, 90°— B, p. 126. Napier's Principles. 1. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts. Draw BD and DE, respectively perpendicular to OH and OP, and draw BE. BDE is a right... | |
| Horatio Nelson Robinson - 1875 - 288 pages
...of the middle part, is equal to the product of the tangents of the adjacent parts. 2d. Radius into **the sine of the middle part, is equal to the product of the** cosines of the opposite parts. The parts are the two sides, the complements of the hypotenuse, and... | |
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