 | Eli Todd Tappan - Geometry - 1868 - 444 pages
...next to it are the adjacent parts, and the remaining two are the opposite parts. Napier's rule is : The sine of the middle part is equal to the product of the tangents of the adjacent parts, also to the product of the cosines of the opposite parts. The words sine and middle... | |
 | Sir Norman Lockyer - Electronic journals - 1872 - 540 pages
...included in the two rules known as Napier's rules, that the sine of the middle (that is, of any chosen) part is equal to the product of the tangents of the two adjacents, as well as to the product of the cosines of the two opposite parts. As a rule to assist... | |
 | William Chauvenet - Trigonometry - 1871 - 268 pages
...considered, the two sides including it are regarded as adjacent parts. The rules are : I. The tine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite... | |
 | Henry W. Jeans - 1873 - 272 pages
...selected is called the middle part. Eule A will apply to the former case, Eule B to the latter. EULE A. The sine, of the middle part is equal to the product of the tangents of the two parts adjacent to it. * The complement of an angle is what it wants of 90° ; thus, in the , P right-angled... | |
 | Aaron Schuyler - Measurement - 1873 - 506 pages
...90°— h, b. 9. 90°— h, 90°— P, b. 10. 90°— P, 90°— B, p. 126. Napier's Principles. 1. The sine of the middle part is equal to the product of the tangents of the adjacent parts. Draw BD and DE, respectively perpendicular to OH and OP, and draw BE. BDE is a right... | |
 | Henry William Jeans - 1873 - 292 pages
...substituted for cos. со. A ; cos. A for sin. со. A ; cot. A for tan. со. A, to. (See Part II.) EULE B. The sine of the middle part is equal to the product of the cosines -of the two parts opposite to, or separated from it.* Having written down the equation according... | |
 | Aaron Schuyler - Measurement - 1864 - 512 pages
...OZi = OE= cos A = sin (90°— A). . • . (5) sin (900— A) = tan (90°— Б) tan (90°— P). 2. The sine of the middle part is equal to the product of the cosines of the opposite parts. OE=cos EOD X OD, or cos A = cos b cos p. ... (6) sin (90°— A) = cos... | |
 | Aaron Schuyler - Navigation - 1873 - 536 pages
...cosEODxOD=OE=coa h = sin (90°— A). . • . (5) sin (90°— A) = tan (90°— B) tan (90°— P). 2. Sine of the middle part is equal to the product of the co-sines of the opposite parts. = cos EOD X OD, or cos h = cos 6 cos p. ... (6) sin (90°— A) = cos... | |
 | Aaron Schuyler - Measurement - 1875 - 276 pages
...90°— Л, b. 9. 90°— A, 90'— P, b. 10. 90°— P, 90°— B, p. 126. Napier's Principles. 1. The sine of the middle part is equal to the product of the tangents of the adjacent parts. Draw BD and DE, respectively perpendicular to OH and OP, and draw BE. BDE is a right... | |
 | Horatio Nelson Robinson - 1875 - 288 pages
...of the middle part, is equal to the product of the tangents of the adjacent parts. 2d. Radius into the sine of the middle part, is equal to the product of the cosines of the opposite parts. The parts are the two sides, the complements of the hypotenuse, and... | |
| |
II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
