| John Daniel Runkle - Mathematics - 1860 - 590 pages
...RULE I. The sine of the middle part equals the product of the cosines of the opposite parts, RULE II. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts. It must be remembered that, instead of the hypothenuse and the two acute angles, their... | |
| Horatio Nelson Robinson - Geometry - 1860 - 472 pages
...of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into **the sine of the middle part is equal to the product of the** cosines of the opposite parts. These rules are known as .Napier's Rules, because they were first given... | |
| George Roberts Perkins - Geometry - 1860 - 470 pages
...RULES. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and... | |
| Edward Butler (A.M.) - 1862 - 154 pages
...in the following rule, which is called Napier's Rule of circular parts :— The sine of a circular **part is equal to the product of the tangents of the two adjacent** circular- parts, or to the product of the cosines of the opposite circular parts. Suppose a and b given,... | |
| Benjamin Greenleaf - Geometry - 1862 - 532 pages
...NAPIER. I. The sine of the middle part is equal to Hie product of tlte tangents of the adjacent parts. IL **The sine of the middle part is equal to the product of the** cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
| Benjamin Greenleaf - Geometry - 1862 - 518 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
| Elias Loomis - Plane trigonometry - 1862 - 202 pages
...required may then be found by the following i RULE OF NAPIER. (211.) The product of the radius and **the sine of the middle part, is equal to the product of the** t&ngents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
| Benjamin Greenleaf - Geometry - 1861 - 638 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of** tJie cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with... | |
| Benjamin Greenleaf - Geometry - 1863 - 504 pages
...I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. . II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
| William Chauvenet - Trigonometry - 1924 - 268 pages
...angle not being considered, the two sides including it are regarded as adjacent parts. The rules are : **I. The sine of the middle part is equal to the product of the** tangente of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
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