 | John Daniel Runkle - Mathematics - 1860 - 590 pages
...RULE I. The sine of the middle part equals the product of the cosines of the opposite parts, RULE II. The sine of the middle part is equal to the product of the tangents of the adjacent parts. It must be remembered that, instead of the hypothenuse and the two acute angles, their... | |
 | Horatio Nelson Robinson - Geometry - 1860 - 472 pages
...of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal to the product of the cosines of the opposite parts. These rules are known as .Napier's Rules, because they were first given... | |
 | George Roberts Perkins - Geometry - 1860 - 470 pages
...RULES. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and... | |
 | Edward Butler (A.M.) - 1862 - 154 pages
...in the following rule, which is called Napier's Rule of circular parts :— The sine of a circular part is equal to the product of the tangents of the two adjacent circular- parts, or to the product of the cosines of the opposite circular parts. Suppose a and b given,... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...NAPIER. I. The sine of the middle part is equal to Hie product of tlte tangents of the adjacent parts. IL The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | Elias Loomis - Plane trigonometry - 1862 - 202 pages
...required may then be found by the following i RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the t&ngents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist... | |
 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of tJie cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. . II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the... | |
 | William Chauvenet - Trigonometry - 1924 - 268 pages
...angle not being considered, the two sides including it are regarded as adjacent parts. The rules are : I. The sine of the middle part is equal to the product of the tangente of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines... | |
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II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
