...and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two...

...square of the root sought, that is, the proposed number, contains the square of the tens, plus twice the product of the tens by the units, plus the square of the units. But the square of the tens must give at least hundreds; hence the last two figures, 44, can form no...

...the square of this - - - 2116 Square of 4 tens, or 40 - - - - 1600 516 This remainder contains twice the product of the tens by the units, plus the square of the units. Now, if we double the tens, which gives 80, and divide 516 by 80, the quotient is the figure of the...

...and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two...

...that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1, 2, 3, 4, &c, tens, or units of the second order, by annexing to each...

...in the root, and also at the right of the divisor, we multiply by 7, and obtain 469, which is twice the product of the tens by the units plus the square of the units. Hence we deduce the following RULE. *• Separate the number into periods of two figures each, by placing...

...which we bring down the two next figures 84. The result of this operation, 1184, contains twice t/te product of the tens by the units^ plus the square of the units. * But since tens multiplied by units cannot give a product of a less name than tens, it follows that...

...and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two...

...6 3 + 6 32+3x6 3'+2(3x6)+6 H The square of a number is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. The same may be shown by the figure : Let the line AB re- F 30 IP present the 3 tens or 30, and BC...

...the same units' figure, must equal the product of the tens by the tens, plus the product of the sum of the tens by the units, plus the square of the units. Show the truth of the following equations : — 67 times 37 = 60 times 30 -f- 7 times 90 + 7 times...