 | Royal Geographical Society (Great Britain) - Scientific expeditions - 1906 - 512 pages
...together with the line AB form an enclosed figure, then the sum of all the interior angles should be equal to twice as many right angles as the figure has sides, less four right angles. We thus have a check on the observed horizontal angles. It should be carefully... | |
 | Henry Sinclair Hall - 1908 - 286 pages
...GEOMETRY. COROLLARY 1. ^M <Ae interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Let ABCDE be a rectilineal figure of & sides. It is required to prove that all the interior angles... | |
 | Walter Percy Workman - Geometry - 1908 - 228 pages
...angles ; and in any convex polygon the sum of the interior angles, together with four right angles, is equal to twice as many right angles as the figure has sides (Euc. I. 32, Cor.) 110 Congruence. CI — If two triangles have two sides and the included angle in... | |
 | Euclid - Mathematics, Greek - 1908 - 550 pages
...somewhat simpler than, Simson's. 1. The sum of the interior angles of a convex rectilineal figure is equal to twice as many right angles as the figure has sides, less four. For let one angular point A be joined to all the other angular points with which it is not... | |
 | Charles E. Larard, Henry A. Golding - Engineering - 1909 - 558 pages
...angles. = 180' (fig. 2). FIG. 1. FIG. 2. The sum of the interior angles of any rectilineal figure is equal to twice as many right angles as the figure has sides, less 4. Thus, for example, in the irregular pentagon (fig. 3), = 2 x 5 x 90° - 4 x 90° ; FIG. 3.... | |
 | Geometry, Plane - 1911 - 192 pages
...whose altitude is 3 inches. SEPTEMBER, 1909 1. The sum of all the interior angles of any polygon is equal to twice as many right angles as the figure has sides, less four right angles. 2. The angle between two chords which intersect within a circle is measured... | |
 | Great Britain. Board of Education - Education - 1912 - 1048 pages
...half BC. 2. Prove that the interior angles of any rectilinear figure together with four right angles are equal to twice as many right angles as the figure has sides. Find the number of sides of a regular polygon, each angle of which is equal to the sum of an angle... | |
 | Alberta. Department of Education - Education - 1912 - 244 pages
...28—1. 6 8. Prove that all the interior angles of any rectilineal figure together with four right angles are equal to twice as many right angles as the figure has sides. 8 9. (a) If a straight line be bisected and produced to any point, the rectangle contained by the whole... | |
 | Great Britain. Board of Education - Mathematics - 1912 - 632 pages
...half BC. 2. Prove that the interior angles of any rectilinear figure together with four right angles are equal to twice as many right angles as the figure has sides. Find the number of sides of a regular polygon, each angle of which is equal to the sum of an angle... | |
 | Alfred Hubert Haines, A. F. Hood Daniel - Building - 1915 - 360 pages
...fulfilled :— 1. All the interior deduced or observed angles together with four right angles must be equal to twice as many right angles as the figure has sides. 2. The northings must equal the southings. 3. The eastings must equal the westings. In ordinary traverse... | |
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All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
