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" All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. "
Elementary Course of Geometry ... - Page 23
by Charles William Hackley - 1847 - 103 pages
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The geometry of the three first books of Euclid, by direct proof from ...

Euclides - 1856 - 168 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and...
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A Treatise on Land-surveying: Comprising the Theory Developed from Five ...

William Mitchell Gillespie - Surveying - 1857 - 538 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. "...
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Elements of Geometry and Trigonometry from the Works of A. M. Legendre ...

Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has sides, less four right angles (p. 26). Hence, the interior angles plus four right angles, is equal to twice...
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Elements of Geometry and Conic Sections

Elias Loomis - Conic sections - 1858 - 256 pages
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are equal to twice as many right angles as the figure has sides, wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ; of a pentagon,...
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The Practice of Engineering Field Work, Applied to Land, Hydrographic, and ...

W. Davis Haskoll - Civil engineering - 1858 - 422 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given...
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A Course of Mathematics: Composed for the Use of the Royal Military Academy

Charles Hutton - Mathematics - 1860 - 1020 pages
...Hence it lotIons that the sum of all the inward angles of the polygon alone, A -f- В — -f. D -f. E, is equal to twice as many right angles as the figure has side*, «am¡ng the said tour right angles- Q. !•'- D. THEOREM xx. When every side of any figure...
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The examination papers as set for the preliminary literary examination of ...

Royal college of surgeons of England - 1860 - 332 pages
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects...
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The Mathematical Monthly, Volume 2

1860 - 462 pages
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are equal to twice as many right angles as the figure has sides minus four right angles, or if « be the number of sides, the sum of all the angles is (2n — 4) right...
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A complete set of male pupil teachers' examination questions in Euclid [book ...

W J. Dickinson - Geometry - 1879 - 44 pages
...produced to meet, the angles formed by these lines, together with eight right angles, are together equal to twice as many right angles as the figure has sides. Same proposition. ABC is a triangle right-angled at A, and the angle B is double of the angle C. Show...
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The Civil-engineer & Surveyor's Manual

Michael McDermott - Civil engineering - 1879 - 552 pages
...future operations. 213. All the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. Example. Interior angles A, B, C, D, E, F = n° 4 right angles, 860 Sum = n° + 360° Namber of sides...
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