 | Elias Loomis - Conic sections - 1858 - 256 pages
...the thre angles of each of these triangles, is equal to tw» right angles (Prop. XXVII.) ; therefore the sum of the angles of all the triangles, is equal to twice as many right angles as the polygon has sides. But the same angles are equal to the angles of the polygon, together with the angles... | |
 | W. Davis Haskoll - Civil engineering - 1858 - 422 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given... | |
 | Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must be equal to twice as many right angles as the figure has sides. But the sum of these angles contains the sum of four right angles about the point p ; taking these away, and the remainder... | |
 | Royal college of surgeons of England - 1860 - 332 pages
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects... | |
 | Charles Hutton - Mathematics - 1860 - 1020 pages
...Hence it lotIons that the sum of all the inward angles of the polygon alone, A -f- В — -f. D -f. E, is equal to twice as many right angles as the figure has side*, «am¡ng the said tour right angles- Q. !•'- D. THEOREM xx. When every side of any figure... | |
 | 1860 - 462 pages
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are equal to twice as many right angles as the figure has sides minus four right angles, or if « be the number of sides, the sum of all the angles is (2n — 4) right... | |
 | Robert Potts - Geometry, Plane - 1860 - 380 pages
...figure together with four right angles ; but it has been proved that the angles of the triangles are equal to twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many... | |
 | William Schofield Binns - 1861 - 238 pages
...Euc. I., 32, Cor. 1, "All the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides." From this corollary, we can deduce a formula for finding the angle of any polygon. Let x equal the... | |
 | Moffatt and Paige - 1879 - 474 pages
...together with four right angles. But it has been proved that all the angles of all these triangles are equal to twice as many right angles as the figure has sides. Therefore all the angles of the figure, together with four right angles, are equal to twice as many... | |
 | William Frothingham Bradbury - Geometry - 1880 - 260 pages
...sides minus two. Let ABCDEF be the given polygon ; the sum of all the interior angles A, B, C, D, E, F, is equal to twice as many right angles as the figure has sides minus two. For if from any vertex A, diagonals AC, AD, AE, are drawn, the polygon will be divided into... | |
| |
All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
