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" ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... "
Daboll's Complete Schoolmaster's Assistant Being a Plain Comprehensive ... - Page 183
by Nathan Daboll - 1843 - 240 pages
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Introduction to the National Arithmetic ...

Benjamin Greenleaf - 1851 - 332 pages
...in division, for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4 . Find...
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Ray's Algebra Part Second: An Analytical Treatise, Designed for High Schools ...

Joseph Ray - Algebra - 1852 - 408 pages
...right, after the manner of a quotient in division. Subtract the square of the root from the kft period, and to the remainder bring down the next period for a dividend. 3rd. Dovlle the root already found, and place it on the left for a divitor. Find how many times the...
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Ray's Algebra, Part First: On the Analytic and Inductive Methods of ...

Joseph Ray - Algebra - 1848 - 250 pages
...right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Double the root already found, and place it on the left for a divisor. Find how many times the...
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The Computist's Manual of Facts: And Merchant's and Mechanic's Calculator ...

Ezra S. Winslow - Business mathematics - 1853 - 264 pages
...now stands, by the figure last placed in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take the product...
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Indroduction to the National Arithmetic ...

Benjamin Greenleaf - 1854 - 342 pages
...in division, for the first figure of the root, and the square number under the period, subtracting it therefrom ; and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor, 4. Find...
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An Introduction to Arithmetic: Containing the Most Useful Rules in Common ...

James Gray - Arithmetic - 1854 - 120 pages
...that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend...
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Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,...
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A New System of Arithmetic, on an Improved Plan, Embracing the Rules of ...

Charles Guilford Burnham - 1857 - 342 pages
...lefthand period, and place it as a, quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the...
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Burnham's Arithmetic, Revised: A New System of Arithmetic, on an Improved ...

Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...lefthand period, and place it as a quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,...
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Practical Arithmetic, by Induction and Analysis

Joseph Ray - Arithmetic - 1857 - 348 pages
...and place its root on the right. as in division. Subtract the cube of the root from the left period, and' to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial, divisor. Find how many times this divisor...
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