 | John Playfair - Circle-squaring - 1819 - 350 pages
...; and the angles in it BAC, BEC are equal, by the first case : For the same reason, ' because CBED is greater than a semicircle, the angles CAD, CED...THEOR. The opposite angles of any quadrilateral figure described in a circle, ate together equal to two right angles. Let ABCD be a quadrilateral figure in... | |
 | John Playfair - 1819 - 354 pages
...semicircle ; and the angles in it BAC, BEC are equal, by the first case : For the suave reason, because CBED is greater than a semicircle, the angles CAD, CED...BED. Wherefore the angles in the same segment, &c. Q, ED PROP. XXII. THEOR. The opposite angles of any quadrilateral figure described in a circle, are... | |
 | Euclid, Robert Simson - Geometry - 1821 - 514 pages
...equal, by the first case; for the same reason because CBED is greater than a semicircle, the anglesCAD, CED are equal: therefore the whole angle BAD is equal...THEOR. The opposite angles of any quadrilateral figure described in a circle, are together equal to two right angles. Let ABCD be a quadrilateral figure in... | |
 | Peter Nicholson - Mathematics - 1825 - 1046 pages
...and the angles in it ВАС, ВЕС are equal, by die first case : For the same reason, because CBED is greater than a semi-circle, the angles CAD, CED are equal : Therefore the whole angle BAD is equa. to the whole angle BED. Wherefore the angles in Jie same segment, &c. QED ' Proposition XXII.... | |
 | Euclid, John Playfair - Euclid's Elements - 1826 - 326 pages
...BEC are equal, by the first ease: For th.e same reason, beeause CBED is greater than a semieirele, the angles CAD> CED are equal; Therefore the whole...whole angle BED.. Wherefore the angles in the same sea* raent, &e. QED « I PROP. XXII. THEOR. The opposite angles of any quadrilateral figure deseribed... | |
 | Robert Simson - Trigonometry - 1827 - 546 pages
...semicircle ; and the angles in it BAC, BEC are equal, by the first case: for the same reason, because CBED is greater than a semicircle, the angles CAD, CED, are equal: therefore the whole angle BAD is equalf t2Ax. to the whole angle BED. Wherefore the angles in the same segment, &c. QED PROP. XXII.... | |
 | Physics - 1828 - 524 pages
...the solidity. 10 70. Parallelograms upon equal bases and between the same parallels are equal. 80. The opposite angles of any quadrilateral figure, inscribed...a circle, are together equal to two right angles. 81. If two triangles have one angle in one equal to one angle in the other, and the sides about the... | |
 | Euclid, Robert Simson - Geometry - 1829 - 548 pages
...semicircle ; and the angles in it, BAC, BEC are equal, by the first case ; for the same reason because CBED is greater than a semicircle, the angles CAD, CED...THEOR. THE opposite angles of any quadrilateral figure described in a circle, are together equal to two right angles. Let ABCD be a. quadrilateral figure... | |
 | University of Cambridge - 1831 - 552 pages
...Caius. FRIDAY MORNING, January 14, 1831. 9 o'clock, to 11. First, Second, Third and Fourth Classes. 1. THE opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. 2. Describe an equilateral and equiangular pentagon about a given circle. 3. What sum must be paid... | |
 | Euclides - 1834 - 518 pages
...than a semicircle, the angles CAD, CED are equal ; t 2 Ax. therefore the whole angle BAD is equal -j. to the whole angle BED. Wherefore, the angles in the same segment, &c. '.>• /:. /.. PROPOSITION XXII. THEOR. — The opposite angles of any quadrilateral Jigure inscribed... | |
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CBED is greater than a semicircle, the angles CAD, CED are equal : therefore the whole angle BAD is, equal to the whole angle BED. 
