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" AA' and BB' be perpendicular to line CD, the projection of line AB upon line CD is line A'B'. PROP. XXV. THEOREM 277. In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice... "
Elements of Plane Geometry - Page 136
by Franklin Ibach - 1882 - 196 pages
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Plane Geometry

Webster Wells, Walter Wilson Hart - Geometry, Plane - 1915 - 330 pages
...THEOREM 310. In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other upon it. Hypothesis. In A ABC, ZB is acute. Conclusion....
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Plane Geometry

Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry, Plane - 1915 - 296 pages
...Theorem. In any triangle, the square of a side opposite an acute angle is equivalent to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other side upon it. Fio. 2 Given the triangle ABC, having an...
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Plane Geometry

John Wesley Young, Albert John Schwartz - Geometry, Modern - 1915 - 248 pages
...236.4. 202 OBLIQUE TRIANGLES 463. THEOREM. In any triangle the square of any side is equal to the sum of the squares of the other two sides minus twice the product of these sides and the cosine of the included angle. AD FIG. 209. Given the triangle ABC. To prove that...
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Plane and Solid Geometry

Webster Wells, Walter Wilson Hart - Geometry - 1916 - 490 pages
...THEOREM 310. In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other upon it. A Hypothesis. In A ABC, ZB is acute. Conclusion....
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Plane Geometry

Edith Long, William Charles Brenke - Geometry, Modern - 1916 - 292 pages
...+ ai2, we have c2 = a2 + 2 aib + 62. State the theorem proved. Why? Why? Why? Why? 119. Theorem XI. In any triangle the square on the side opposite an acute angle is equal to the sum of the squares on the other two sides, diminished by twice the product of one of...
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Plane Geometry

Edith Long, William Charles Brenke - Geometry, Plane - 1916 - 292 pages
...+ c^2, we have c2 = a2 + 2 aj> + b\ State the theorem proved. Why? Why? Why? Why? 119. Theorem XI. In any triangle the square on the side opposite an acute angle is equal to the sum of the squares on the other two sides, diminished by twice the product of one of...
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Mathematics for Collegiate Students of Agriculture and General Science

Alfred Monroe Kenyon, William Vernon Lovitt - Mathematics - 1917 - 368 pages
...the given side. 100. Law of Cosines. In any triangle, the square of any side is equal to the sum of the squares of the other two sides minus twice the product of these two sides into the cosine of their included angle. V, ยง 100] TRIGONOMETRY Let ABC be any triangle....
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Plane Geometry: With Problems and Applications

Herbert Ellsworth Slaught, Nels Johann Lennes - Geometry, Plane - 1918 - 360 pages
...ANGLE 375. THEOREM. The square of the side opposite an acute angle of a triangle is equal to the sum of the squares of the other two sides minus twice the product of one of these sides and the projection of the other upon it. c Outline of proof. In either figure let ZB be...
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Plane Geometry, with Problems and Application

Herbert Ellsworth Slaught - 1918 - 344 pages
...ANGLE 375. THEOREM. The square of the side opposite an acute angle of a triangle is equal to the sum of the squares of the other two sides minus twice the product of one of these sides and the projection of the other upon it. c Outline of proof. In either figure let ZB be...
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Plane and Solid Geometry

Claude Irwin Palmer, Daniel Pomeroy Taylor - Geometry - 1918 - 460 pages
...Theorem. In any triangle, the square of a side opposite an acute angle is equivalent to the sum of the squares of the other two sides, minus twice the product of one of these- sides and the projection of the other side upon it. FIG. 2 Given the triangle ABC, having an...
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