 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...to the trial divisor for a complete divisor ; multiply tlie complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period for a new dividend. V Multiply the last figure of the last complete divisor... | |
 | James Stewart Eaton - 1862 - 320 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...divisor; add the correction, and the result will be the complete divisai'. V. Multiply the. complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring flown another period for a new dividend. VI. Add together the last complete divisor, the last... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...the quotient in the root, and also annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but... | |
 | James Stewart Eaton - Arithmetic - 1864 - 322 pages
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...divisor; add the correction, and the result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...figure ; annex the result both to the root and the divisor. 4. Multiply the divisor thus increased by the last figure of the root; subtract the product from the, dividend, and to the remaindet bring down the next period for a new dividend. 5. Double the whole root now found for a new... | |
 | Stoddard A. Felter - Arithmetic - 1864 - 430 pages
...the trial divisor, will form the complete divisor. V. Multiply and subtract, as in simple division, and, to the remainder, annex the next period for a new dividend. VI. Proceed in the same manner as before, until all the periods are brought down. NOTES. — 1. If... | |
 | Charles Davies - Arithmetic - 1865 - 372 pages
...the root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...the figure in the root and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor,... | |
| |
Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... 
