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... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude.
Plane and Solid Geometry - Page 155
by Claude Irwin Palmer, Daniel Pomeroy Taylor - 1918 - 436 pages

## Plane and Solid Geometry

Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...THEOREM. Two parallelograms having equal bases are to each other as their altitudes. Proof: (?). 377. THEOREM. Any two parallelograms are to each other as the products of their bases by their altitudes. Proof: (?). 378. THEOREM. The area of a triangle is equal to half the product of...

## New Plane Geometry

Webster Wells - Geometry, Plane - 1908 - 206 pages
...other as their bases. 3. Two parallelograms having equal bases are to each other as their altitudes. 4. Any two parallelograms are to each other as the products of their bases by their altitudes. Ex. 4. The area of a parallelogram is 288, the base is twice the altitude. Find...

## New Plane and Solid Geometry

Webster Wells - Geometry - 1908 - 336 pages
...other as their bases. 3. Two parallelograms having equal bases are to each other as their altitudes. 4. Any two parallelograms are to each other as the products of their bases by their altitudes. Ex. 4. The area of a parallelogram is 288, the base is twice the altitude. Find...

## Wentworth's Plane Geometry

George Albert Wentworth, David Eugene Smith - Geometry, Plane - 1910 - 287 pages
...each other as their altitudes; parallelograms having equal altitudes are to each other as their bases; any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM 325. The area of a triangle is equal to half the product...

## Plane Geometry

Clara Avis Hart, Daniel D. Feldman - Geometry, Modern - 1911 - 328 pages
...Cor. I. The area of a square is equal to the square of its side. 479. Cor. n. Any two rectangles are to each other as the products of their bases and their altitudes. OUTLINE or PROOF. Denote. the two rectangles by R and B-, their bases by b and b', and their altitudes...

## Solid Geometry

Clara Avis Hart, Daniel D. Feldman, Virgil Snyder - Geometry, Solid - 1912 - 230 pages
...base and its altitude. 482. Parallelograms having equal bases and equal altitudes are equivalent. 483. Any two parallelograms are to each other as the products of their bases and their altitudes. 484. (a) Two parallelograms having equal bases are to each other as their altitudes, and (4) two parallelograms...

## Plane Geometry

William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Plane - 1912 - 360 pages
...ABEF. area rectangle ABEF = bh. .'. area O ABCD = bh. That is, 5. But Ax. 2 Why ? 329. COROLLARY 1. Two parallelograms are to each other as the products of their bases and altitudes. 330. COROLLARY 2. Two parallelograms having equal bases are to each other as their altitudes....

## Plane Geometry

William Betz, Harrison Emmett Webb - Geometry, Modern - 1912 - 368 pages
...HABCD = rectangle ABEF. 5. But area rectangle ABEF = bh. Why ? .'. area n ABCD = bh. 29. COROLLARY 1. Two parallelograms are to each other as the products of their bases and altitudes. 330. COROLLARY 2. Two parallelograms having equal bases are to each other as their altitudes....