 Hence, the area of a trapezoid is equal to the product of its altitude by the line connecting the middle points of the sides which are not parallel.  Advanced Arithmetic - Page 223by John William McClymonds, David Rhys Jones - 1910 - 324 pagesFull view - About this book
 | Walter Burton Ford, Earle Raymond Hedrick - Geometry, Modern - 1913 - 272 pages
...Outline of Proof. Draw the diagonal BD. Then A ABD = ah/2 and A BCD = bh/2 ; hence Why? 192. Corollary 1. The area of a trapezoid is equal to the product of its altitude and the line joining the mid-points of the nonparallel sides. DC FIG. 133 [HINT. To prove area of ABCD... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Plane - 1913 - 378 pages
...Outline of Proof. Draw the diagonal BD. Then A ABD = ah/2 and A BCD = bh/2; hence Why? 192. Corollary 1. The area of a trapezoid is equal to the product of its altitude and the line joining the mid-points of the nonparallel sides. DC FIG. 133 [HINT. To prove area of ABC'D... | |
 | William Betz - Geometry - 1916 - 536 pages
...= $bh, §333 and area AADC = ^ b'h. 4. .'. area trapezoid ABCD = \ h(b + b'). Ax. 2 336. COROLLARY. The area of a trapezoid is equal to the product of its altitude and mid-line. § 219 EXERCISES 1. From § 321 derive a proof for the above theorem by means of the figure... | |
 | John Charles Stone, James Franklin Millis - Geometry - 1916 - 306 pages
...Suggestion. Draw DB. Prove that A ABD = l ab and A DCB = \ ac. Then add and factor. 226. Corollary. — The area of a trapezoid is equal to the product of its altitude and the line-segment joining the middle points of its non-parallel sides. See § 98. 227. Area of any polygon.... | |
 | William Betz, Harrison Emmett Webb - Geometry, Solid - 1916 - 214 pages
...The area of a trapezoid is equal to half the product of its altitude and the sum of its bases. 336. The area of a trapezoid is equal to the product of its altitude and mid-line. 337. If two triangles have an angle of one equal to an angle of the other, their areas are... | |
 | Jacob William Albert Young, Lambert Lincoln Jackson - Geometry, Plane - 1916 - 328 pages
...ABC=$hb, Why? and A ACD = \ hb'. Why ? 3. .-. trapezoid ABCD = A ACD + A ABC = QED 365. COROLLARY. The area of a trapezoid is equal to the product of its altitude by the line joining the mid-points of the nonparallel sides. According to Sec. 166, the line joining... | |
 | Fletcher Durell, Elmer Ellsworth Arnold - Geometry, Plane - 1917 - 330 pages
...to 12' 10 ' 20 20 1/6" __^ 13' W 25' 40' 28' (2) CJ) AREAS OF POLYGONS PROPOSITION VII. THEOREM 350. The area of a trapezoid is equal to the product of its altitude and half the sum of its parallel sides. Given the trapezoid AB CD with the bases AD and BC (denoted by... | |
 | Herbert Ellsworth Slaught - 1918 - 344 pages
...area A ACD = $bh + % b'h. § 411 .-. Area ABCD = i bh + i b'h = \ h(b + b'). °- B- D418. COROLLARY. The area of a trapezoid is equal to the product of its altitude and its median. Suggestion. Use § 187. EXPERIMENTAL GEOMETRY 1. In the figure, the two triangles are similar... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Geometry, Plane - 1918 - 360 pages
...$bh + ± b'h. § 411 .-. Area ABCD = %bh + J- b'h = \h(b + b'). Q- «• »• 418. COROLLARY. Tlie area of a trapezoid is equal to the product of its altitude and its median. Suggestion. Use § ]87. EXPERIMENTAL GEOMETRY 1. In the figure, the two triangles are similar... | |
 | Charles Austin Hobbs - Geometry, Solid - 1921 - 216 pages
...Prop. 151, Cor. III. Two triangles having equal bases are to each other as their altitudes. Prop. 152. The area of a trapezoid is equal to the product of its altitude and one half the sum of its bases. Prop. 153. Two triangles haring an angle of one equal to an angle of the other are to each other as... | |
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