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" Prove that parallelograms on the same base and between the same parallels are equal in area. "
Science Examination Papers - Page 243
by Great Britain. Education Department. Department of Science and Art - 1899
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Report of the Council of Public Instruction of the North-West Territories of ...

Northwest Territories Council of Public Instruction - 1897 - 628 pages
...parallel ; (ii) with one pair parallel ; (iii) with two pairs parallel. (J) Prove that parallelograms on the same base and between the same parallels are equal in area. I. 35. (f) Point out the uses of proposition (I) in mensuration. (d) Prove that if a square and a rhombus...
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Mathematics: Mechanic's bids and estimates. Mensuration for beginners. Easy ...

Seymour Eaton - 1899 - 362 pages
...EBCH. Therefore the parallelogram ABCD is equal to the parallelogram EFQII. PROPOSITION 37. THEOREM Triangles on the same base, and between the same parallels, are equal. Let the triangles ABC, DBC be on the same base BC, and between the same parallels AD, BC ; then the...
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A Text-book of Euclid's Elements for the Use of Schools. Books I.-VI ..., Book 1

Euclid, Henry Sinclair Hall, Frederick Haller Stevens - Euclid's Elements - 1900 - 330 pages
...(ii) Parallelograms on equal bases and of equal altitudes are equal in area. PROPOSITION 37. THEOREM. Triangles on the same base, and between the same parallels, are equal in area. Let the triangles ABC, DEC be upon the same base BC, and between the same parallels BC, AD. Then shall...
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Sessional Papers, Volume 22, Part 2

Great Britain. Parliament. House of Commons - Great Britain - 1900 - 686 pages
...angles shall be equal to one another. .10. Define parallel straight lines and prove that parallelograms on the same base and between the same parallels are equal in area. 11. A square field contains 15 ac. 2 ro. 20 per.; find the length of a path crossing it diagonally....
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Special Reports on Educational Subjects, Volumes 6-7

Great Britain. Board of Education - Education - 1900 - 906 pages
...angles shall be equal to one another. 10. Define parallel straight lines and prove that parallelograms on the same base and between the same parallels are equal in area. 11. A square field contains 15 ac. 2 ro. 20 per. ; find the length of a path crossing it, diagonally....
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Report of the Department of Education for the Year ...

Manitoba. Department of Education - Education - 1900 - 558 pages
...drawn from two angles of a triangle and terminated by the opposite sides can bisect one another. 4. Two .triangles on the same base and between the same parallels are equal. By means of this proposition show how to describe a triangle equal to a given quadrilateral ; and Bisect...
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Woolwich Mathematical Papers for Admission Into the Royal Military Academy ...

Eldred John Brooksmith - Mathematics - 1901 - 368 pages
...Examination may be used in the solution of problems and riders. 1. Prove that two triangles standing on the same base and between the same parallels are equal in area. Hence show that if two triangles have two sides of the one equal to two sides of the other and the...
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A Text-book of Euclid's Elements for the Use of Schools, Book 1

Euclid - Euclid's Elements - 1904 - 488 pages
...parallelogram is equal in area to a rectangle of equal base and equal altitude. PROPOSITION 37. THEOREM. Triangles on the same base, and between the same parallels, are equal in area. Let the triangles ABC, DBC be upon the same base BC, and between the same parallels BC, AD. Then shall...
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A Manual of Carpentry and Joinery

J. W. Riley - Carpentry - 1905 - 522 pages
...work it graphically, finding a rectangle of equal area. This is done by an application of the fact that triangles on the same base and between the same parallels are equal in area (Fig. 157, p. 93). Produce AB and join AD. Through E draw EF parallel to DA ; then the triangles AFD...
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A Manual of Carpentry and Joinery

J. W. Riley - Carpentry - 1905 - 518 pages
...height area = base xr ā€” c Sā€” . 2i The shape of the triangle does not affect the result, as all triangles on the same base and between the same parallels are equal in area. The area of a triangle can also be determined by the following formula : \^s(s - a)(s - b)(x - ,')...
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