 | Benjamin Greenleaf - Arithmetic - 1860 - 456 pages
...the true divisor, which multiply by the last root figure and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new trial divisor, and continue the operation as before, till all... | |
 | Charles Davies - Arithmetic - 1861 - 496 pages
...annex it to the divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the...period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue the operation as before, until all the periods are... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...root and also at the right of the divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend,...remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish the last figure of the root... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...the root (the breadth of the additions), and subtract the contents of the additions thus obtained, from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new divisor, and continue the operation as before, until all... | |
 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...figure last annexed by the figure annexed to the root. and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new divisor, and continue th*. operation as before, till all the... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...the TO EXTRACT THE CTJRE EOOT. sura of the three parts will be the complete divisor, which multiply by the last figure of the root, and subtract the product...remainder bring down the next period for a new dividend. Proceed in same way, until all the periods are brought down. EXAMPLE. Find the cube root of 111215247129.... | |
 | Elias Loomis - Algebra - 1862 - 312 pages
...the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. If the product should be greater than the dividend, diminish the last figure of the root. 5. Double... | |
 | James Bates Thomson - Arithmetic - 1862 - 436 pages
...of the partial divisor ; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, &c., as before, and thus continue... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...trial divisor for a complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the...bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor, with which... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but one figure ; each of the others will contain two.... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
