 | Robert Miller (M.A., of Edinburgh.) - Arithmetic - 1881 - 238 pages
...x perpendicular height. TRIANGLE: Area = a8e * p- — -, or from half the sum of the 4 three sides subtract each side separately. Multiply the half sum and the three remainders together, and take the square root of the product. SPHERE: Area=D" x 3-1416; solid contents = TI» x -5236 ;... | |
 | Daniel W. Fish - Arithmetic - 1883 - 348 pages
...whose base is 20 ft. and each, of the other sides 15 ft RULE. — From half the sum of the three sides subtract each side separately ; multiply the half...remainders together ; the square root of the product is the area. 3. Find the area of a triangle whose sides are 25, 36, and 49 in. 4. How many acres in... | |
 | William Waterston - 1884 - 314 pages
...6. The three fides of a triangle being given, toßnd the area: From half the sum of the three sides subtract each side separately ; multiply the half...together; the square root of the product will be the ares. Ex. If the sides be S6, 28, and 30 Inches, we have 26 + 28 + 30 = 84, and ft 84 =42; also 42... | |
 | Euclides - 1884 - 434 pages
...c); which expression may be put into the form of a rule, thus : From half the sum of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will be the area.* 1. If from B there be drawn BE j_ AC or AC produced,... | |
 | Colin Arrott R. Browning - 1884 - 274 pages
...the length of each side, but not the perpendicular. Rule : — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root of this product will be the area of triangle. (16) In a right-angled... | |
 | Andrew Jackson Rickoff - Arithmetic - 1886 - 688 pages
...When the three sides of a triangle are given, to find the area : From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product. The Trapezoid. —Example. — Given the length of each... | |
 | Edward Richard Shaw - Examinations - 1887 - 360 pages
...breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and extract the square root of the product. 247. Multiply the base by the altitude. 248. Multiply the... | |
 | Edward Richard Shaw - 1887 - 488 pages
...breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and extract the square root of the product. 247. Multiply the base by the altitude. 248. Multiply the... | |
 | Andrew Jackson Rickoff - 1888 - 464 pages
...When the three sides of a triangle are given, to find the area: From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product. length of each of the two parallel sides of a / A/ The... | |
 | John Groesbeck - 1891 - 426 pages
...the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product. EXAMPLES. 1. What is the area of a triangle whose sides... | |
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From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 
