 | Elias Loomis - Geometry - 1871 - 302 pages
...opposite angle on the base produced. Let ABC be an obtuse-angled triangle, having the obtuse angle ABC, and from the point A let AD be drawn perpendicular to BC produced ; the square of AC is greater than the squares of AB, BC by twice the rectangle BC x BD. For... | |
 | Euclides - 1874 - 342 pages
...perpendicular and the obtuse angle, Let ABC be an obtuse-angled triangle, having the obtuse angle ACB; and from the point A, let AD be drawn perpendicular to BC produced. Then the square on AB shall be greater than the squares on AC, CB, by twice the rectangle... | |
 | Edward Atkins - 1874 - 426 pages
...perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle ACB; and from the point A let AD be drawn perpendicular to BC produced. The square on AB shall be greater than the squares on AC and CB by twice the rectangle BC,... | |
 | Euclides - 1874 - 120 pages
...and the obtuse angle. j f. Let ABC be an obtuse-angled triangle, having If ยป' the obtuse angle ACB, and from the point A let AD be drawn perpendicular to BC produced : the square on AB shall be greater than the squares on AC, CB, by twice the rectangle BC,... | |
 | Edward Atkins - 1876 - 130 pages
...perpendicular and the obtuse angle. Let ABC be an obtuse- angled triangle, having the obtuse angle ACB; and from the point A let AD be drawn perpendicular to BC produced. The square on AB shall be greater than the squares on AC and CB by twice the rectangle BC,... | |
 | Moffatt and Paige - 1879 - 506 pages
...perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle ACB, and from the point A let AD be drawn perpendicular to BC produced. Then the square on AB shall be greater than the squares on AC, CB by twice the rectangle... | |
 | Stewart W. and co - 1884 - 272 pages
...perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle ACB, and from the point A, let AD be drawn perpendicular to BC produced. Then the square of AB is greater than the squares of AC, CB, by twice the rectangle BC, CD.... | |
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... which, when produced, the perpendicular falls, and the straight line intercepted, without the triangle, between the perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle ACB, and from the point A let AD... 
