 | Daniel Adams - Arithmetic - 1828 - 266 pages
...Hence, when the extremes and the number of terms are given, '.o find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will b« the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...Hence, when the. extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | William Kinne - 1829 - 246 pages
...term, the last term, and the number of terms being given, to find the sum of all the terms. HOLE. — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical progression is... | |
 | Dudley Leavitt - Mathematics - 1830 - 154 pages
...instead of $ 353.50. 16. "If 1000 bricks lie 6 inches from each other in a straight line," &c. Solution. Multiply the sum of the extremes by the number of terms, and half of the product is the answer. 1st. In going from the pile to the first brick, and carrying that... | |
 | Daniel Adams - Arithmetic - 1830 - 280 pages
...Hence, when the extremes and the number of terms are given, to find the sum of all the terms,- — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...) Hence, when the extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ th'e sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...Hence, when the extremes, and the number of terms are given, to find the sum of all the terms ; — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 3 and 373, and the number of terms 40, what... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...extremes and the number of terms being given, to find the sum of all the termsofthe progression. RULE. — Multiply the sum of the extremes by the number of terms, and half of the product will be the sum of the series : Or, multiply one of those factors by half of the... | |
 | Daniel Adams - Arithmetic - 1833 - 268 pages
...) Hence, when the extremes and the member of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 6OS, ?nd the number of terms 151, what... | |
 | Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...the following rule ; When the extremes and number of terms are given, to find the sum of the terms, Multiply the sum of the extremes by the number of terms, and divide the product by 2. 2. The first term of a series is 1, the last term 29, and the number of terms... | |
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Multiply £ the sum of the extremes by the number of terms, and the product will be the answer 10. 
