 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...the same kind, the first term, and that which is of the same kind as the answer, the second term. 2.f Multiply the second and third terms together, and divide the product by the first, the quotient will be the answer. EXAMPLE. — If 8lb. of sugar cost $1.00, what will 401b-. of sugar... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...do you proceed in the operation ? A. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. VII . How may this process of multiplying and dividing be, in most cases, materially... | |
 | Thomas Tucker Smiley - 1830 - 188 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term was reduced.... | |
 | Daniel Adams - Arithmetic - 1830 - 294 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Daniel Adams - Arithmetic - 1830 - 280 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
 | Arithmetic - 1831 - 198 pages
...second terms be not of the same denomination, reduce one or both of them till they are; and if the third term consist of several denominations, reduce it to...product by the first term: the quotient will be the answer. Note. — The product of the second and third termsis of the same denomination as the third... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...Then multiply the second and third terms together, and divide their product by the first term, and the quotient will be the fourth term, or answer, in. the same denomination as the third term; which may be brought into any other denomination required.^ Note 1. — When the third... | |
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Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. 
