 To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square on the other part.  Euclid - Page 138by Euclid, Rupert Deakin - 1903 - 164 pagesFull view - About this book
 | Euclides - Geometry - 1853 - 176 pages
...С d. Wherefore, if a straight line, &c. QED PROPOSITION XI. — PROBLEM. To divide a given straigM line into two parts, so that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. LET ab be the given straight line... | |
 | William Walton, Charles Frederick Mackenzie - Education - 1854 - 266 pages
...BD the other diameter, the difference of the parallelograms is equal to twice the triangle BSD. 2. Divide a given straight line into two parts so that...rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight line to a point such that... | |
 | Cambridge univ, exam. papers - 1854 - 284 pages
...BD the other diameter, the difference of the parallelograms is equal to twice the triangle BKD. 2. Divide a given straight line into two parts so that...rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight line to a point such that... | |
 | Robert Potts - 1855 - 1050 pages
...that iSj divides them into two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part Solve the same problem algebraically,... | |
 | Euclides - 1855 - 270 pages
...the square of the straight line which joins the points of the bisection of the diagonals. . PROP. D. PROBLEM. — To divide a given straight line into two parts so that the rectangle contained by its segments shall be equal to a given square, not greater than the square of half the given straight... | |
 | Great Britain. Committee on Education - School buildings - 1855 - 976 pages
...upon the other two sides of it, the angle contained by those two sides is a right angle. 3. Divide a straight line into two parts, so that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. Section 3. 1. The angles in the... | |
 | John Playfair - Geometry - 1855 - 334 pages
..., and the proposition is evident from this algebraical equality. PROP. XI. PROB. To divide a givrn straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part. I Let AB be the given straight... | |
 | Cambridge univ, exam. papers - 1856 - 200 pages
...contained by the whole and each of the parts are together equal to the square of the whole line. 7. To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. 8. If a straight line drawn through... | |
 | Cambridge univ, exam. papers - 1856 - 252 pages
...contained by the whole and each of the parts, are together equal to the square of the whole line. 7. Divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. 8. If two circles cut one another,... | |
 | Henry White - 1856 - 168 pages
...one side of it are either two right angles, or are together equal to two right angles. 18 Divide a straight line into two parts, so that the rectangle contained by the whole and ono of the parts shall be equal to the square of the other part. 19 If two circles cut each other,... | |
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