| 1885 - 608 pages
...that the sum of the interior angles of any rectilineal figure together witli four right angles, is **equal to twice as many right angles as the figure has sides.** 5. Prove that the opposite sides and angles of a parallelogram are equal to one another, and that the... | |
| Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...eight right angles, or $ of one right angle. Cor. 4. In any equiangular polygon, any interior angle is **equal to twice as many right angles as the figure has sides,** less four right angles, divided by the mimber of angles. PROPOSITION XXVII. THEOREM. The sum of the... | |
| William Davis Haskoll - Hydrographic surveying - 1886 - 354 pages
...of the angles having been correctly measured, because all the interior angles of the polygon will be **equal to twice as many right angles as the figure has sides,** less four right angles, or 360°, if the theodolite has been correctly used. There will, however, generally... | |
| Webster Wells - Geometry - 1886 - 392 pages
...angles is expressed by 2 R x (n — 2) , or 2 nR — 4 R. That is, the sum of the angles of a polygon is **equal to twice as many right angles as the figure, has sides,** less four right angles. PROPOSITION XLVII. THEOREM. 149. If the sides of a polygon are produced so... | |
| Richard Anthony Proctor - Geometry - 1887 - 202 pages
...produced to meet, the angles formed by these lines, together with eight right angles, are together **equal to twice as many right angles as the figure has sides.** 139. AP, BP, and CP are the internal bisectors of the angles of the triangle ABC. AP is produced to... | |
| Bennett Hooper Brough - Mine surveying - 1888 - 366 pages
...accuracy of the survey, as the interior angles of the polygon together with four right angles should be **equal to twice as many right angles as the figure has sides.** The interior angles of a traverse may be found from the bearings or courses by the following rules... | |
| E. J. Brooksmith - Mathematics - 1889 - 354 pages
...the given line, shew how to draw the perpendicular without producing the given line. 1. Prove that **all the interior angles of any rectilineal figure,...twice as many right angles as the figure has sides.** There are two regular polygons, the number of sides of one is double the number of sides of the other,... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 538 pages
...ACB together=two rt. ^s; [I. 13. ... LS CBA, BAC, BCA together=two rt. ^s. [Ax. 1. COROLLARY I.— **All the interior angles of any rectilineal figure,...twice as many right angles as the figure has sides.** D For any rectl. figure, ABCDE, can be divided into as many As as the figure has sides by drawing st.... | |
| John Fry Heather - Geometry, Modern - 1890 - 252 pages
...one-third of two right angles, or to 60°. 63. THEOE. 6. All the interior angles of any rectilinieal **figure together with four right angles, are equal...twice as many right angles as the figure has sides** (Euc. I. 32. Cor. 1). Hence the angles of a regular polygon are each equal to the quotient obtained... | |
| Edward Albert Bowser - Geometry - 1890 - 420 pages
...2 rt. Zs (n — 2) = 2n rt. Zs — 4 rt. Zs. Therefore, the sum of the angles of a polygon is also **equal to twice as many right angles as the figure has sides,** less four right angles. 149. COR. 2. The sum of the angles of a quadrilateral is equal to two right... | |
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