 | American School (Chicago, Ill.) - Engineering - 1903 - 426 pages
...—, 69. Divide 16 ab by 8 a. 16 a Ь 8a = 26. Monomials. To find the coefficient of the quotient, divide the coefficient of the dividend by the coefficient of the divisor. 70. To find the exponent of any letter of the quotient, »ubtract the exponent of the letter of the... | |
 | Arthur William Potter - Algebra - 1904 - 182 pages
...have unlike signs, the sign of the quotient must be — . x RULE. To divide one monomial by another, divide the coefficient of the dividend by the coefficient of the divisor for the coefficient of the quotient. To this quotient annex all the different letters, giving each letter... | |
 | Frederick Howland Somerville - Algebra - 1905 - 222 pages
...sign of the quotient, + or - according as the signs of the dividend and divisor are like or unlike. Divide the coefficient of the dividend by the coefficient of the divisor and affix the sign obtained. Annex the literal factors, giving to each an exponent equal to the difference... | |
 | Frederick Howland Somerville - Algebra - 1908 - 428 pages
...а3a?у2. . = _ 5 a5-3¡,:3-32^-2 _ _ 5 aгyí Result. 7, Hence, to divide a monomial by a monomial : 81. Divide the coefficient of the dividend by the coefficient of the divisor, annexing to the result the literal factors, each 1vith an exponent equal to its exponent in the dividend... | |
 | Jacob William Albert Young - 1908 - 344 pages
...from that of the dividend. For example: o»_ tf"_ 149. To find the quotient of two positive monomials divide the coefficient of the dividend by the coefficient of the divisor, and to this quotient annex each letter with an exponent equal to the exponent of that letter in the... | |
 | Jacob William Albert Young, Lambert Lincoln Jackson - Algebra - 1908 - 460 pages
...subtract the exponent of the divisor from that of the dividend. 149. To find the quotient of two monomials divide the coefficient of the dividend by the coefficient of the divisor, and to this quotient annex each letter with an exponent equal to ike exponent of that letter in the... | |
 | Albert Harry Wheeler - Algebra - 1908 - 700 pages
...the radicands of the dividend and divisor. for the coefficient of the radical part of the quotient divide the coefficient of the dividend by the coefficient of the divisor, and for the radicand of the quotient divide the radicand of the dividend by the radicand of the divisor.... | |
 | James William Nicholson - Algebra - 1909 - 332 pages
...-s. ó = 1, because 1 xb = b c3 -H e = с2, because с2 x с = e3. Hence, the quotient is - 3 а"с2. Divide the coefficient of the dividend by the coefficient of the divisor, observing the law of signs. To this quotient annex each literal factor of the dicidend with an exponent... | |
 | Fletcher Durell, Edward Rutledge Robbins - Algebra - 1909 - 296 pages
...Arts. 62, 63, 64, we have the following general process for the division of one monomial by another : Divide the coefficient of the dividend by the coefficient of the divisor ; trading the exponent of each letter in the divisor from the exponent of the same letter in the dividend... | |
 | Fletcher Durell - Algebra - 1912 - 300 pages
...in Arts. 60, 61, and 62, we have the following method for the division of one monomial by another: Divide the coefficient of the dividend by the coefficient of the divisor; Obtain the exponent of each literal factor in the quotient by subtracting the exponent of each letter... | |
| |
I. Divide the coefficient of the dividend by the coefficient of the divisor. 
